Re: [Dev-C++] copying elements to an array of pointers...

[Per W. <pw...@ia...>]

But most proably that wasn't the intention.

The fact that both array and string was sized with max must mean
something... in this case a failed attempt at space for the characters. By
mistake, the declaration instead created a number of pointers.

char *ptr;
char string[max];

ptr = new char[max];
strncpy(ptr,string,max);
ptr[max-1] = '\0';

or instead
string[max-1] = '\0';
ptr = strdup(string);

/Per W

On Sun, 27 Oct 2002, Abhijit Shylanath wrote:

> > got a question:
> > i'd like to copy a char string to a string of pointers but i can't get the
> > code working...and i can't see the result with cout... anyone who can help
> > me??
> > kind regards,
> > senem
> 
> > #include <iostream.h>
> > #include <stdlib.h>
> > #include <string.h>
> > #include <stdio.h>
> > #define max 5
> > int main(){
> >  char *array[max];
> 
> Here, you've just declared an array of pointers. You haven't actually
> allocated memory, so the pointers are not valid. You need to new[] it, like
> so.
> 
>     array[0] = new char[max];
> 
> and so on.
> 
> >  char string[max];
> >  cout<<"enter string :";
> >  cin.getline(string,max);
> >  strncpy(array[0],string,sizeof(string)/sizeof(char));
> > cout<<array[0];
> >  return 0;
> > }
> 
> ___________________________________________________________
> 
> Abhijit Shylanath
> 
> E-mail:   mu...@gm... || ibr...@bi...
> Web-site: http://mudeth.tripod.com/
> 
> 
> 
> 
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