RE: [Dev-C++] Why doesn't this compile?

[Ioannis V. <no...@ho...>]

> -----Original Message-----
> From: dev...@li...=20
> [mailto:dev...@li...] On Behalf=20
> Of Andrew Vidler
> Sent: Wednesday, October 09, 2002 6:36 PM
> To: 'C++ Dev'
> Subject: RE: [Dev-C++] Why doesn't this compile?
>=20
>=20
> Absolutely. Sorry, I'm probably not being very clear :)
> MY_TYPE *p =3D *c
> Does work, problem is, what I'm looking for is some operator=20
> that does:
> MY_TYPE *p =3D c;
>=20
> I don't think this is possible...but you never know!


Ok you have confused things. Forget the whole thing completely. Just do:

// Example
#define MY_TYPE int

CBase	*c =3D new CDerived;


If you want to point to it using some pointer of entirely foreign type,
this means you must know what you are doing and use a cast (in your case
the ugliest of all, reinterpret_cast).


MY_TYPE *f =3D reinterpret_cast<MY_TYPE *>(c);



Forget those operators you were using.


Ioannis

* Ioannis Vranos
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