RE: [Dev-C++] Why doesn't this compile?

[Andrew V. <av...@in...>]

Ummm...MY_TYPE can be any type, change it to "float" if you like,
doesn't make any difference like I said.
I know the constructors etc... aren't strictly needed, they don't stop
it compiling or working though.
Also, the constructors etc... *are* required for the actual
implementation - this is just a stripped down and renamed version for
test perposes.

Oh, and I disagree with the "better to 'return 0'" comment :)
0 is an integer, I know NULL is just #defined as 0, but using NULL
implies a pointer type.
You wouldn't type the following:

UINT I = 27 + NULL;

Would you?, so why write:

UINT *p = 0;

?

-----Original Message-----
From: dev...@li...
[mailto:dev...@li...] On Behalf Of Ioannis
Vranos
Sent: 09 October 2002 15:54
To: 'C++ Dev'
Subject: RE: [Dev-C++] Why doesn't this compile?


> -----Original Message-----
> From: dev...@li...
> [mailto:dev...@li...] On Behalf
> Of Andrew Vidler
> Sent: Tuesday, October 08, 2002 10:53 PM
> To: C++ Dev
> Subject: [Dev-C++] Why doesn't this compile?
>
>
> And more importantly, how can I make it compile?!
>
>
>
> #define MY_TYPE IDirect3DBaseTexture8
>
> class CBase
> {
> 	public:
> 		CBase() {}


Not needed.


> 		virtual ~CBase() {}


Or better: virtual ~CBase();



>
> 		virtual operator MY_TYPE * () = 0;


Where is IDirect3DBaseTexture8 defined?



> };
>
> class CDerived : public CBase
> {
> 	public:
> 		CDerived() {}
> 		~CDerived() {}


You can ommit the above two.


>
> 		operator MY_TYPE * () { return NULL; }

Better: return 0;


IDirect3DBaseTexture8 not defined anywhere.



> };
>
> void	test()
> {
> 	CBase	*c = new CDerived();
> 	MY_TYPE *f = c;
> }
>
>
>
>
> The #define is there purely so I could see if the code compiled with
> different types - it doesn't.


Ioannis

* Ioannis Vranos
* Programming pages: http://www.noicys.freeurl.com
* Alternative URL: http://run.to/noicys




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