RE: [Dev-C++] sizeof array

[Ioannis V. <no...@ho...>]

sizeof() reports the total size of the array when it is used in the
scope of its definition.

When you use an array as an argument of a function in reality it is not
an array but a pointer.


consider the following example:

void makea(char array[100])
{
  while(*array)
    *array++='a';
}


int main()
{
  char somearray[500];
  
  for(unsigned long i=0; i<sizeof(somearray)-2; i++)
    somearray[i]='s';
    
  somearray[sizeof(somearray)-1]='\0';
  
  
  makea(somearray);
}  




void makea(char array[100]) is equivallent to void makea(char *array)
and void makea(char array[])


So sizeof(array) when applied inside the makea() is equivallent to
sizeof(char *).

array there is char *array.


Ioannis

* Ioannis Vranos
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