RE: [Dev-C++] Array of function pointers

[Ioannis V. <no...@ho...>]

> -----Original Message-----
> From: dev...@li... 
> [mailto:dev...@li...] On Behalf 
> Of Abhijit Shylanath
> Sent: Sunday, June 30, 2002 9:27 PM
> To: Dev-C++ Mailing List
> Subject: [Dev-C++] Array of function pointers
> 
> 
> Sorry for my repeated OT posts, but I don't subscribe to many 
> lists because
> they have too much of traffic, and poor little me has a 
> dial-up account. Of
> all the lists I do subscribe to, Dev-C++ seems to have the most
> knowledgeable (and tolerant) people.
> 
> Having finished buttering you up, here's my question:



Always ask. That is why this list is for. Coders talking with coders. :)


> How do I create an array of function pointers?
> 
> I declare a function pointer as:
> 
>     void (*fnPtr)(int arg1) = fn;


Or better: void (*fnPtr)(int);





> I tried making an array like this:
> 
>     void *(*fnPtrs)(int)


This is a pointer to a function returning void * and getting an int.



> 
> Didn't work.
> 
>     void (*fnPtrs)(int)[] = { fn, foo, NULL };


void (*fnPtrs[])(int) = { fn, foo, NULL };


Or if you cannot think that big, you can make things simpler:


typedef void (*p2f)(int);
  
p2f fnPtrs[]= { fn, foo, NULL };



> Didn't work either.
> 
> Ultimately, I got frustrated and made an array of dwords:
> 
>     dword fnPtrs[] = { (dword)fn, (dword)foo, (dword)NULL };
> 
> This worked, without any warnings. Is this portable and safe?


It depends on what dword is, but it doesn't sound safe.


 
> Is there any
> other ANSI way of making an array of function pointers?
> 
> Thanks for any help.



Ioannis

* Ioannis Vranos
* Programming pages: http://www.noicys.cjb.net
* Alternative URL: http://run.to/noicys