RE: [Dev-C++] 2 questions

[Hongli L. <h....@ch...>]

On Wed, 2002-06-19 at 18:47, Mac Reiter wrote:
> I'm a little disturbed by the description given below.  I'm pretty sure
> that argc includes the name of the executable, so that "bot.exe level3.bot"
> would have argc == 2.  I know that argv[0] contains the name of the
> executable, because UN*X systems use this to distinguish behaviors for
> symlinked executables (don't ask, it isn't possible on Windows, and it is
> slightly odd anyway).  The practical upshot is that, for the example above,
> argv[0] would be "bot.exe" and argv[1] would be "level3.bot".
> 

Actually, argv[0] is always the full filename of the executable, like
C:\Foo\Bar.exe, no matter what you do. In Unix, argv[0] is what you've
typed in at the commandline, not the filename of the executable.