RE: [Dev-C++] short integer problem

[Ioannis V. <no...@ho...>]

Also in my system, short ss was too small to store 64000 and the results
got truncated. That's why i made it int.




Ioannis

* Ioannis Vranos
* Programming pages: http://www.noicys.cjb.net
* Alternative URL: http://run.to/noicys


> -----Original Message-----
> From: Ioannis Vranos [mailto:no...@ho...]=20
> Sent: Friday, June 07, 2002 3:59 PM
> To: Dev-C++ Mailing List
> Subject: RE: [Dev-C++] short integer problem
>=20
>=20
> Yes it has the bug, because he used wrong format specifiers. For short
> he should use %hd. Also in a variadic function, when the=20
> passed type is
> different from the type specifier a casting should be used (e.g.
> printf("\n sizeof(short): %d",(int)sizeof(short)); ).
>=20
>=20
> #include <stdio.h>
> #include <stdlib.h>
>=20
>=20
> int main(void)
> {
>    short x,y, entries;     /* declared as int program works as
> expected */
>    int ss;
>    printf("\n sizeof(short): %d",(int)sizeof(short));
>    printf("\n2 to the 15: %d\n\n",128*128*2);
>    printf("\n Enter 2 int values: \n");
>    entries=3Dscanf("%hd",&x);
>    entries +=3Dscanf("%hd",&y);
>    printf("\n x=3D %hd   y=3D %hd",x,y);
>=20
>    while (entries =3D=3D 2) {
>        printf("\n x=3D %hd   y=3D %hd",x,y);
>        printf("\nX+Y =3D %hd",x+y);
>        printf("\nX-Y =3D %hd",x-y);
>        printf("\nX*Y =3D %hd",x*y);
>        printf("\nX/Y =3D %hd",x/y);
>        printf("\nx %c y =3D %hd\n",'\045',x%y);
>=20
>        ss =3D 64000;
>        printf("\nEnter a short int");
>        scanf("%d",&ss);
>        printf("\n Another try on a short int gives: %d",ss);
>        printf("\n Enter 2 int values: ");
>        entries=3Dscanf("%hd%hd",&x,&y);
>    }
>=20
>    printf("\n\n");
>    system("PAUSE");
>       return 0;
> }
>=20
>=20
>=20
>=20
>=20
>=20
> Ioannis
>=20
> * Ioannis Vranos
> * Programming pages: http://www.noicys.cjb.net
> * Alternative URL: http://run.to/noicys
>=20
>=20
> > -----Original Message-----
> > From: dev...@li...=20
> > [mailto:dev...@li...] On Behalf=20
> > Of Juliano P=E1vel Brasil Cust=F3dio
> > Sent: Friday, June 07, 2002 4:23 AM
> > To: dev...@li...
> > Subject: RE: [Dev-C++] short integer problem
> >=20
> >=20
> > 	Rob, I didn't got any error message when I tried to compile and
> > run your program. By the way, I'm working with an Athlon
> > 800MHz/WinXP/DevCpp 4.9.3.0.
> >=20
> > 	Juliano
> >=20
> > -----Original Message-----
> > From: dev...@li...
> > [mailto:dev...@li...] On Behalf=20
> > Of rchavez
> > Sent: quinta-feira, 6 de junho de 2002 19:08
> > To: dev...@li...
> > Subject: [Dev-C++] short integer problem
> >=20
> >=20
> > Hi,
> >=20
> > While trying a problem from my text 'A Book on C' I ran into some
> > strange behavior for short integers.  If I use integers, the program
> > below reads them in & performs the arithmetic correctly.  But if I
> > change line 3 so the variables are of type short, the value of x is
> > always 0 !!
> >=20
> > I've played with it a lot but can't find the problem.  Any=20
> > help would be
> > appreciated.  Also, notice that the scanf for var ss at the bottom
> > always works.  It's not a gcc bug since I get the same behavior on a
> > unix compiler.
> >=20
> > Rob
> >=20
> > /** Math on Short Integers **/
> >=20
> > main()
> > {
> >    short x,y, entries=3D2;     /* declared as int program works as
> > expected */
> >    short ss;
> >    printf("\n sizeof(short): %d",sizeof(short));
> >    printf("\n2 to the 15: %d\n\n",128*128*2);
> >    printf("\n Enter 2 int values: \n");
> >    entries=3Dscanf("%d",&x);
> >    entries +=3Dscanf("%d",&y);
> >    printf("\n x=3D %d   y=3D %d",x,y);
> >=20
> >    while (entries =3D=3D 2) {
> >        printf("\n x=3D %d   y=3D %d",x,y);
> >        printf("\nX+Y =3D %d",x+y);
> >        printf("\nX-Y =3D %d",x-y);
> >        printf("\nX*Y =3D %d",x*y);
> >        printf("\nX/Y =3D %d",x/y);
> >        printf("\nx %c y =3D %d\n",'\045',x%y);
> >=20
> >        ss =3D 64000;
> >        printf("\nEnter a short int");
> >        scanf("%d",&ss);
> >        printf("\n Another try on a short int gives: %d",ss);
> >        printf("\n Enter 2 int values: ");
> >        entries=3Dscanf("%d%d",&x,&y);
> >    }
> >=20
> >    printf("\n\n");
> >    system("PAUSE");
> >       return 0;
> > }
> >=20
> > _______________________________________________________________
> >=20
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> >=20
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> >=20
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> >=20
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