RE: [Dev-C++] short integer problem

[Ioannis V. <no...@ho...>]

Yes it has the bug, because he used wrong format specifiers. For short
he should use %hd. Also in a variadic function, when the passed type is
different from the type specifier a casting should be used (e.g.
printf("\n sizeof(short): %d",(int)sizeof(short)); ).


#include <stdio.h>
#include <stdlib.h>


int main(void)
{
   short x,y, entries;     /* declared as int program works as
expected */
   int ss;
   printf("\n sizeof(short): %d",(int)sizeof(short));
   printf("\n2 to the 15: %d\n\n",128*128*2);
   printf("\n Enter 2 int values: \n");
   entries=3Dscanf("%hd",&x);
   entries +=3Dscanf("%hd",&y);
   printf("\n x=3D %hd   y=3D %hd",x,y);

   while (entries =3D=3D 2) {
       printf("\n x=3D %hd   y=3D %hd",x,y);
       printf("\nX+Y =3D %hd",x+y);
       printf("\nX-Y =3D %hd",x-y);
       printf("\nX*Y =3D %hd",x*y);
       printf("\nX/Y =3D %hd",x/y);
       printf("\nx %c y =3D %hd\n",'\045',x%y);

       ss =3D 64000;
       printf("\nEnter a short int");
       scanf("%d",&ss);
       printf("\n Another try on a short int gives: %d",ss);
       printf("\n Enter 2 int values: ");
       entries=3Dscanf("%hd%hd",&x,&y);
   }

   printf("\n\n");
   system("PAUSE");
      return 0;
}






Ioannis

* Ioannis Vranos
* Programming pages: http://www.noicys.cjb.net
* Alternative URL: http://run.to/noicys


> -----Original Message-----
> From: dev...@li...=20
> [mailto:dev...@li...] On Behalf=20
> Of Juliano P=E1vel Brasil Cust=F3dio
> Sent: Friday, June 07, 2002 4:23 AM
> To: dev...@li...
> Subject: RE: [Dev-C++] short integer problem
>=20
>=20
> 	Rob, I didn't got any error message when I tried to compile and
> run your program. By the way, I'm working with an Athlon
> 800MHz/WinXP/DevCpp 4.9.3.0.
>=20
> 	Juliano
>=20
> -----Original Message-----
> From: dev...@li...
> [mailto:dev...@li...] On Behalf=20
> Of rchavez
> Sent: quinta-feira, 6 de junho de 2002 19:08
> To: dev...@li...
> Subject: [Dev-C++] short integer problem
>=20
>=20
> Hi,
>=20
> While trying a problem from my text 'A Book on C' I ran into some
> strange behavior for short integers.  If I use integers, the program
> below reads them in & performs the arithmetic correctly.  But if I
> change line 3 so the variables are of type short, the value of x is
> always 0 !!
>=20
> I've played with it a lot but can't find the problem.  Any=20
> help would be
> appreciated.  Also, notice that the scanf for var ss at the bottom
> always works.  It's not a gcc bug since I get the same behavior on a
> unix compiler.
>=20
> Rob
>=20
> /** Math on Short Integers **/
>=20
> main()
> {
>    short x,y, entries=3D2;     /* declared as int program works as
> expected */
>    short ss;
>    printf("\n sizeof(short): %d",sizeof(short));
>    printf("\n2 to the 15: %d\n\n",128*128*2);
>    printf("\n Enter 2 int values: \n");
>    entries=3Dscanf("%d",&x);
>    entries +=3Dscanf("%d",&y);
>    printf("\n x=3D %d   y=3D %d",x,y);
>=20
>    while (entries =3D=3D 2) {
>        printf("\n x=3D %d   y=3D %d",x,y);
>        printf("\nX+Y =3D %d",x+y);
>        printf("\nX-Y =3D %d",x-y);
>        printf("\nX*Y =3D %d",x*y);
>        printf("\nX/Y =3D %d",x/y);
>        printf("\nx %c y =3D %d\n",'\045',x%y);
>=20
>        ss =3D 64000;
>        printf("\nEnter a short int");
>        scanf("%d",&ss);
>        printf("\n Another try on a short int gives: %d",ss);
>        printf("\n Enter 2 int values: ");
>        entries=3Dscanf("%d%d",&x,&y);
>    }
>=20
>    printf("\n\n");
>    system("PAUSE");
>       return 0;
> }
>=20
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