RE: [Dev-C++] short integer problem

[<jp...@bo...>]

	Rob, I didn't got any error message when I tried to compile and
run your program. By the way, I'm working with an Athlon
800MHz/WinXP/DevCpp 4.9.3.0.

	Juliano

-----Original Message-----
From: dev...@li...
[mailto:dev...@li...] On Behalf Of rchavez
Sent: quinta-feira, 6 de junho de 2002 19:08
To: dev...@li...
Subject: [Dev-C++] short integer problem


Hi,

While trying a problem from my text 'A Book on C' I ran into some
strange behavior for short integers.  If I use integers, the program
below reads them in & performs the arithmetic correctly.  But if I
change line 3 so the variables are of type short, the value of x is
always 0 !!

I've played with it a lot but can't find the problem.  Any help would be
appreciated.  Also, notice that the scanf for var ss at the bottom
always works.  It's not a gcc bug since I get the same behavior on a
unix compiler.

Rob

/** Math on Short Integers **/

main()
{
   short x,y, entries=2;     /* declared as int program works as
expected */
   short ss;
   printf("\n sizeof(short): %d",sizeof(short));
   printf("\n2 to the 15: %d\n\n",128*128*2);
   printf("\n Enter 2 int values: \n");
   entries=scanf("%d",&x);
   entries +=scanf("%d",&y);
   printf("\n x= %d   y= %d",x,y);

   while (entries == 2) {
       printf("\n x= %d   y= %d",x,y);
       printf("\nX+Y = %d",x+y);
       printf("\nX-Y = %d",x-y);
       printf("\nX*Y = %d",x*y);
       printf("\nX/Y = %d",x/y);
       printf("\nx %c y = %d\n",'\045',x%y);

       ss = 64000;
       printf("\nEnter a short int");
       scanf("%d",&ss);
       printf("\n Another try on a short int gives: %d",ss);
       printf("\n Enter 2 int values: ");
       entries=scanf("%d%d",&x,&y);
   }

   printf("\n\n");
   system("PAUSE");
      return 0;
}

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