RE: [Dev-C++] Case statement - it SHOULD work...

[Ioannis V. <no...@ho...>]

You obviously forgot the '' when you used the char type. '1', '2', '3'.


Ioannis

* Ioannis Vranos
* Programming pages: http://www.noicys.cjb.net
* Alternative URL: http://run.to/noicys


> -----Original Message-----
> From: dev...@li... 
> [mailto:dev...@li...] On Behalf 
> Of Daniel Glenfield
> Sent: Sunday, April 07, 2002 2:04 PM
> To: dev...@li...
> Subject: [Dev-C++] Case statement - it SHOULD work...
> 
> 
> Here's a quick bit of code. For some reason when I enter 1, 
> 2, or 3 I get
> the ERROR!!!!! message. If I change Choice to a char type and 
> change 1 2 and
> 3 to a b and c it works.
> What's wrong?
> 
> int main(int argc, char *argv[])
> {
> 	using namespace std;
> 
> 	int Choice; // Menu choice, as entered by user.
>    do
>    {
> 	 cout << "***** W E L C O M E *****\n";
> 	 cout << "\nChoose one of the following...\n";
>          cout << "1.Create Employee 2.Change wage 3.Exit\n";
> 	 cin >> Choice; // Get user's choice
> 	 switch (Choice) // Beginning our case flow control statements
> 	 {
> 	    case 'a' : cout << "Confirmed - Creating Employee...\n";
> 		           break;
> 		case 'b' : cout << "Confirmed - Changing wage...\n";
> 			       break;
> 		case 'c' : cout << "Exiting...\n";
> 			       break;
> 		default  : cout << "ERROR!!!!!!!!!!!!!!!!\n";
> 	 }
>    }while(Choice > '3' || Choice < '1');
> 
> 
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