[Dev-C++] Re: Palindrome

[Samuel K. <big...@ya...>]

This will only work for base 10 and there are surely many ways of doing the
palindrome that are a lot easier to understand and more economical on
computer processor time but I thought you all might want to take a look.
(don't be to harsh on me, I haven't been programming very long)

#include <iostream>

int main(){

    int inputNumber,
        firstSentinal = 10,         //Counts up Digits

    //varible to "flip"  inputNumber


        secondSentinal = 1,
        editNumber = 0;


    cout << "Please input number:";
    cin >> inputNumber;


    while (inputNumber / firstSentinal >= 10){

          firstSentinal *= 10;
    }

    //Keeps secondSentinal from overflowing

    const int Guard = firstSentinal * 10;

    while ( secondSentinal != Guard ){

          editNumber += (inputNumber / firstSentinal) * secondSentinal;
//Does work of flipping

          inputNumber %= firstSentinal;
          firstSentinal /= 10;
          secondSentinal *= 10;
     }

     cout << endl << editNumber <<"\n\n";





      cin.ignore(256, '\n');
      cout << "Press ENTER to continue..." << endl;
      cin.get();


    return 0;
}


As I said this will only work base ten. To use it for the palindrome make
another const copy of inputNumber and then if editNumber = = inputNumber you
know that it is a palindrome. This might  be portable to hex, but I'm not
sure.


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