I think argv[][] would be a two dimensional array, n'est pas?
Thanks for the information on the whole char* thing, I think I'll go for the
*var type but we'll see (new job today so I guess I'll do what I'm told).
Best regards,
Daniel
>From: "Jason Hardman" <jas...@bt...>
>To: "Dev-C++" <dev...@li...>, "Daniel Glenfield"
><sp...@ho...>
>Subject: Re: [Dev-C++] difference between char* argv[] and char *argv[]
>Date: Mon, 8 Apr 2002 00:17:04 +0100
>
>I know you've been told they are the same by now, which is right, but I
>though I'd add the why of
>the two forms.
>
>There is an argument about which is better between some programmers. Some
>say that "char* variable;"
>is best because the pointer symbol is visibly linked to the char type, so
>it's clear that you are
>declaring a character pointer (a pointer to a character) and not just a
>character. The others say
>that this is misleading as if you write:
>
>char* var1, var2;
>
>it looks like both var1 and var2 are pointers, where as in fact var1 is a
>character pointer and var2
>is just a character, so they say use the second method:
>
>char *var1, *var2; // two pointers
>
>In the end it's a matter of style, both are valid and you can even write
>(AFAIK):
>
>char * var1; // just to confuse you!
>
>There are other arguments, but I don't bother with any of it and just use
>what I want.
>
>Even more confusing (<evil laugh>) is that you can write *argv[], or **argv
>and they are
>interchangeable. I'm not sure about argv[][] though - probably invalid.
>
>My two cents, Jason.
>
>----- Original Message -----
>From: "Daniel Glenfield" <sp...@ho...>
>To: <dev...@li...>
>Sent: Sunday, April 07, 2002 12:07 PM
>Subject: [Dev-C++] difference between char* argv[] and char *argv[]
>
>
>Hi all,
>what's the difference between char* argv[] and char *argv[] ? imilarly,
>char* abc and char *abc ? Are they the SAME because the compiler ignores
>whitespace?
>
>Daniel
>
>
>
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