dev-cpp-users

[Dev-C++] Array of function pointers

[Abhijit S. <mu...@gm...>]

Sorry for my repeated OT posts, but I don't subscribe to many lists because
they have too much of traffic, and poor little me has a dial-up account. Of
all the lists I do subscribe to, Dev-C++ seems to have the most
knowledgeable (and tolerant) people.

Having finished buttering you up, here's my question:
How do I create an array of function pointers?

I declare a function pointer as:

    void (*fnPtr)(int arg1) = fn;

I tried making an array like this:

    void *(*fnPtrs)(int)

Didn't work.

    void (*fnPtrs)(int)[] = { fn, foo, NULL };

Didn't work either.

Ultimately, I got frustrated and made an array of dwords:

    dword fnPtrs[] = { (dword)fn, (dword)foo, (dword)NULL };

This worked, without any warnings. Is this portable and safe? Is there any
other ANSI way of making an array of function pointers?

Thanks for any help.
--------------------------
http://mudeth.tripod.com

Re: [Dev-C++] Array of function pointers

[Hongli L. <h....@ch...>]

On Sun, 2002-06-30 at 20:27, Abhijit Shylanath wrote:
> Sorry for my repeated OT posts, but I don't subscribe to many lists because
> they have too much of traffic, and poor little me has a dial-up account. Of
> all the lists I do subscribe to, Dev-C++ seems to have the most
> knowledgeable (and tolerant) people.
> 
> Having finished buttering you up, here's my question:
> How do I create an array of function pointers?
> 

typedef void (*FooFunction) (int data);

void foo(int data);
void bar(int data);

FooFunction function_array[] = { foo, bar };

RE: [Dev-C++] Array of function pointers

[Ioannis V. <no...@ho...>]

> -----Original Message-----
> From: dev...@li... 
> [mailto:dev...@li...] On Behalf 
> Of Abhijit Shylanath
> Sent: Sunday, June 30, 2002 9:27 PM
> To: Dev-C++ Mailing List
> Subject: [Dev-C++] Array of function pointers
> 
> 
> Sorry for my repeated OT posts, but I don't subscribe to many 
> lists because
> they have too much of traffic, and poor little me has a 
> dial-up account. Of
> all the lists I do subscribe to, Dev-C++ seems to have the most
> knowledgeable (and tolerant) people.
> 
> Having finished buttering you up, here's my question:



Always ask. That is why this list is for. Coders talking with coders. :)


> How do I create an array of function pointers?
> 
> I declare a function pointer as:
> 
>     void (*fnPtr)(int arg1) = fn;


Or better: void (*fnPtr)(int);





> I tried making an array like this:
> 
>     void *(*fnPtrs)(int)


This is a pointer to a function returning void * and getting an int.



> 
> Didn't work.
> 
>     void (*fnPtrs)(int)[] = { fn, foo, NULL };


void (*fnPtrs[])(int) = { fn, foo, NULL };


Or if you cannot think that big, you can make things simpler:


typedef void (*p2f)(int);
  
p2f fnPtrs[]= { fn, foo, NULL };



> Didn't work either.
> 
> Ultimately, I got frustrated and made an array of dwords:
> 
>     dword fnPtrs[] = { (dword)fn, (dword)foo, (dword)NULL };
> 
> This worked, without any warnings. Is this portable and safe?


It depends on what dword is, but it doesn't sound safe.


 
> Is there any
> other ANSI way of making an array of function pointers?
> 
> Thanks for any help.



Ioannis

* Ioannis Vranos
* Programming pages: http://www.noicys.cjb.net
* Alternative URL: http://run.to/noicys

RE: [Dev-C++] Array of function pointers

[Ioannis V. <no...@ho...>]

> -----Original Message-----
> From: dev...@li... 
> [mailto:dev...@li...] On Behalf 
> Of Ioannis Vranos
> Sent: Sunday, June 30, 2002 11:34 PM
> To: 'Dev-C++ Mailing List'
> Subject: RE: [Dev-C++] Array of function pointers
> 
> 
> > -----Original Message-----
> > From: dev...@li...
> > [mailto:dev...@li...] On Behalf
> > Of Abhijit Shylanath
> > Sent: Sunday, June 30, 2002 9:27 PM
> > To: Dev-C++ Mailing List
> > Subject: [Dev-C++] Array of function pointers
> >
> >
> > Sorry for my repeated OT posts, but I don't subscribe to many
> > lists because
> > they have too much of traffic, and poor little me has a
> > dial-up account. Of
> > all the lists I do subscribe to, Dev-C++ seems to have the most
> > knowledgeable (and tolerant) people.
> >
> > Having finished buttering you up, here's my question:
> 
> 
> 
> Always ask. That is why this list is for. Coders talking with 
> coders. :)
> 
> 
> > How do I create an array of function pointers?
> >
> > I declare a function pointer as:
> >
> >     void (*fnPtr)(int arg1) = fn;
> 
> 
> Or better: void (*fnPtr)(int);
> 
> 
> 
> 
> 
> > I tried making an array like this:
> >
> >     void *(*fnPtrs)(int)
> 
> 
> This is a pointer to a function returning void * and getting an int.
> 
> 
> 
> >
> > Didn't work.
> >
> >     void (*fnPtrs)(int)[] = { fn, foo, NULL };
> 
> 
> void (*fnPtrs[])(int) = { fn, foo, NULL };
> 
> 
> Or if you cannot think that big, you can make things simpler:
> 
> 
> typedef void (*p2f)(int);
> 
> p2f fnPtrs[]= { fn, foo, NULL };
> 
> 
> 
> > Didn't work either.
> >
> > Ultimately, I got frustrated and made an array of dwords:
> >
> >     dword fnPtrs[] = { (dword)fn, (dword)foo, (dword)NULL };
> >
> > This worked, without any warnings. Is this portable and safe?
> 
> 
> It depends on what dword is, but it doesn't sound safe.
> 
> 
> 
> > Is there any
> > other ANSI way of making an array of function pointers?
> >
> > Thanks for any help.


If you do it in C++, instead of a built in arrray use a vector of
pointers.

An example:

#include <vector>

// ...

using std::vector;

// ...

vector<void (*)(int)>fnPtrs(2, fn);
  
fnPtrs[1]=foo;



Ioannis

* Ioannis Vranos
* Programming pages: http://www.noicys.cjb.net
* Alternative URL: http://run.to/noicys