False positive with bool bitwise OR

[Nikita Leontiev]

Since cppcheck 2.0 false positive occurs with bool bitwise OR:

#include <inttypes.h>
#include <stdio.h>

int main()
{
    bool f1 = true, f2 = false, f3 = true;
    uint32_t num = (f3 << 2) | (f2 << 1) | f1;
    printf("%#x\n", num);
    return 0;
}

test.cpp:7:42: style:inconclusive: Boolean expression 'f1' is used in bitwise operation. Did you mean '||'? [bitwiseOnBoolean]
    uint32_t num = (f3 << 2) | (f2 << 1) | f1;
                                         ^

[Daniel Marjamäki]

I believe this is by intention. Some people wants that bool variables are treated specially and not used in arithmetic ways. I think it's inspired by Java. Obviously you do not want to have such special handling. Please suppress this warning.