Re: Getting the name of a cllib:xml-obj as a string

[<gm...@av...>]

Easy!

rtos[1]> (cllib:xmln-ln (cllib:xmlo-name foo))
"backslash"

rtos[2]> (type-of (cllib:xmln-ln (cllib:xmlo-name foo)))
(SIMPLE-ARRAY CHARACTER (10))

rtos[3]> (string= (cllib:xmln-ln (cllib:xmlo-name foo)) "backslash")
T

rtos[4]> 

Enjoy!
Gregg Lobdell

> From: Dave Pearson <da...@da...>
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> 
> What is the correct method of getting the name of an xml-obj as a string?
> 
> The reason I ask is that I've got an xml-obj and I can see how to get it's
> name:
> 
> ,----
> | #<cllib:xml-obj backslash [] 21 objects 1,639/2,144 chars #x204E4F69>
> | slashdot[497]> (cllib:xmlo-name foo)
> | "backslash"
> `----
> 
> but, due to the type:
> 
> ,----
> | slashdot[498]> (type-of (cllib:xmlo-name foo))
> | cllib:xml-name
> `----
> 
> I can't compare it with a string:
> 
> ,----
> | slashdot[499]> (string= (cllib:xmlo-name foo) "backslash")
> | 
> | *** - string=: argument "backslash" should be a string, a symbol or a character
> `----
> 
> Currently I'm doing things like:
> 
> ,----
> | slashdot[501]> (string= (format nil "~A" (cllib:xmlo-name foo)) "backslash")
> | t
> `----
> 
> but that feels inelegant. Is there something in xml.lisp that gets me get
> the name as a string or is the a common CL idiom I should be using to
> convert a xmlo-name into a string?
> 
> Alternatively, should I be creating another xmlo-name and comparing what
> I've got with that? How would I go about doing that if that was the answer?
> 
> -- 
> Dave Pearson
> http://www.davep.org/
> 
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