[Barcode4j-users] [ barcode4j-Bugs-2804024 ] PDF417 control character bad encoded

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Bugs item #2804024, was opened at 2009-06-10 11:11
Message generated for change (Comment added) made by jmaerki
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Category: None
Group: None
>Status: Open
>Resolution: Accepted
Priority: 5
Private: No
Submitted By: sucotronic (sucotronic)
Assigned to: Nobody/Anonymous (nobody)
Summary: PDF417 control character bad encoded

Initial Comment:
When I try to generate a barcode with this statement:
bean.generateBarcode(provider,(char)29+(char)29+(char)29+(char)29+(char)29+"B");

and then try to read the result, I get the following:
"145B"

Is it a bug o a encoding missmatching?

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>Comment By: Jeremias Mrki (jmaerki)
Date: 2009-06-11 15:01

Message:
Ok, that latest example indeed seems to trigger a bug. I'll look at it as
soon as I can. No promises for a timely fix. I'm quite busy at the moment.

"5789\u001dB0KLT3215\u001e\u0004"; //good
"45789\u001dB0KLT3215\u001e\u0004"; //bad

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Comment By: sucotronic (sucotronic)
Date: 2009-06-11 13:00

Message:
Ups, I press accidentally the button...
Well, as you can see in previous comment the read data doesn't correspond
with the given string. I'm still thinking is something related with
encoding.

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Comment By: sucotronic (sucotronic)
Date: 2009-06-11 12:58

Message:
Ok. I've done another test with this:
...
kk
="[)>\u001e06\u001d1JUN123456789A2B4C6D8E\u001dP12345678\u001dQ50\u001d2SB0345789\u001dB0KLT3215\u001e\u0004";
bean.generateBarcode(provider,kk);
...
And the result read is:
(text): [)>#06#1JUN123456789A2B4C6D8E#P12345678#Q50#2SB0345789#1A&#/DCBF##
(hex): 5b 29 3e 1e 30 36 1d 31 4a 55 4e 31 32 33 34 35 36 37 38 39 41 32
42 34 43 36 44 38 45 1d 50 31 32 33 34 35 36 37 38 1d 51 35 30 1d 32 53 42
30 33 34 35 37 38 39 1d 31 41 26 0d 2f 44 43 42 46 1e 04 



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Comment By: Jeremias Mrki (jmaerki)
Date: 2009-06-11 11:40

Message:
It's a Java mistake on your side. "char" in Java is an unsigned number.
Until the "B" the Java compiler thinks you want to sum up numbers: 5*29 =
145. It essentially adds the 5 numbers together and then converts that sum
to a string (Integer.toString). You have to do either:
"\u001D\u001D\u001D\u001D\u001DB"
or
""+(char)29+(char)29+(char)29+(char)29+(char)29+"B"

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Comment By: sucotronic (sucotronic)
Date: 2009-06-10 13:21

Message:
I've just downloaded and build the latest version from cvs and the problem
remains.

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