Re: [Aironet] Enquiries of AP3500
Status: Inactive
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From: Jim V. <jv...@bi...> - 2000-06-01 14:50:50
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> ******************************************************************* > Testing link to 004096126bab with 100 unicast packets of size 1024 > FAIR(13% Retries) Time(ms) Strength(%) Retries(%) > In Out In Out > Sent = 100 Avg: 25 3 26 21 5 > Lost to Tgt = 0 Max: 220 10 38 19 1 > Lost to Src = 0 Min: 22 1 4 > ******************************************************************* > > 1. Signal Strength In/Out refers to what ? And the % is based on what > value ? "Signal Strength" is determined from the AP's point of view. "In" refers to a signal being received by the AP from the client. "Out" refers to a signal being received by the client from the AP. In this case - the AP has seen signal strengths ranging from 1% to 10% with an average of 3% from the client. The client is reporting that is has seen a signal strength ranging from 4% to 38% with an average of 26% from the AP. > 2. Does this test provide any info about noise, SNR ? I don't believe so - but I'll check. > 3. How to do a test for frame error rate ? Not exactly sure what you want here... > 4. How to interprete the 'Retries' ? "In" - this corresponds with the amount of retries the client has transmitted. The first number is the total amount of retries - and the second number is the highest retry count for any single packet is 19. The client transmitted a total of 21 retries. (it may have either retried one packet 19 times and two more packets 1 time each, or it retried one packet 19 times and one other packet 2 times) "Out" - this corresponds with the amount of retries FROM the AP to the client. In this case there are a total of 5 retries - with the maximum amount per packet of 1. So - 5 packets each had 1 retry. The "13%" retry measurement on the first line is calculated by dividing the total amount of retries (26 = 5 + 21) by the total amount of packets sent (200). The reason we use 200 instead of 100 is EACH side sent a total of 100 packets. 100 linktest packets result in 100 round trips so each side transmits 100 packets. > 5. 1 frame = ? packets. 1 frame = 1 packet Jim |