From: Carl T. <ce...@ca...> - 2002-04-17 17:43:00
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Quoting Troy Schultz <tsc...@ca...>: > ... > I'm afraid you may have a bigger issue than who is correct for the > percent full calculation. Looking at the numbers you are getting > from your battery, these can not be correct for any current battery > technology unless your battery pack were to be 10 times the size it > is now. > > A Typical high capacity LiON battery pack used in a notebook will > have approx. 4500mWh of capacity, the typical notebook will have a > discharge rate of approx. 1500mWh. This would yield a typical run > time of 4500/1500= 3h. > > You are reading remaining capacity of 43985mWh, which would give you > an enviable, but unreaslistic, runtime of 43985/1500 = 29.3h. > > It seems that for some reason some people are getting results from > their battery packs that are 10 times what they should be. I have > seen this on a few Compaq 700 series notebooks, and a couple others > that I can't recall right now. Actually, no. I believe you are confusing mAh and mWh. Your battery's capacity as written on the battery is in current-time in mAh (milli-Amp-hours) at a particular potential (number of volts) whereas the ACPI code reports capacity as total work remaining in mWh (milli-Watt-hours). For instance, my battery lists its capacity as 3,000mAh at 14.8V which is the same as 44,400mAh of work which is how the ACPI code lists it. Or something like that. > Best Regards > - Troy Schultz Carl Thompson |