User Activity
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Modified
a comment
on
ticket #4032
on
Maxima -- GPL CAS based on DOE-MACSYMA
Maybe this is a bit more simple (some divisions are replaced by multiplications and replace U by 1): [%i*I1*w+(%i*I2)/(C1*w)-(%i*I1)/(C1*w) = 1, %i*I3*w+%i*I2*w+(%i*I3)/(C2*w)-(%i*I2)/(C2*w)-(%i*I2)/(C1*w)+(%i*I1)/(C1*w) = 0, %i*I2*w-(%i*I4)*w-(%i*I3)/(C2*w)+2*(%i*I3)*w+(%i*I2)/(C2*w) = 0, %i*I4*w-(%i*I3)*w+I4 = 0]$ What is remarkable: If you replace the summand 2*(%i*I3)*w by (%i*I3)*w (leave away the constant 2), then Maxima finds the correct solution. If you try to replace other divisions by multiplications,...
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Modified
a comment
on
ticket #4032
on
Maxima -- GPL CAS based on DOE-MACSYMA
Maybe this is a bit more simple (some divisions are replaced by multiplications and replace U by 1): [%i*I1*w+(%i*I2)/(C1*w)-(%i*I1)/(C1*w) = 1, %i*I3*w+%i*I2*w+(%i*I3)/(C2*w)-(%i*I2)/(C2*w)-(%i*I2)/(C1*w)+(%i*I1)/(C1*w) = 0, %i*I2*w-(%i*I4)*w-(%i*I3)/(C2*w)+2*(%i*I3)*w+(%i*I2)/(C2*w) = 0, %i*I4*w-(%i*I3)*w+I4 = 0]$ What is remarkable: If you replace the summand 2*(%i*I3)*w by (%i*I3)*w (leave away the constant 2), then Maxima finds the correct solution. If you try to replace other divisions by multiplications,...
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Modified
a comment
on
ticket #4032
on
Maxima -- GPL CAS based on DOE-MACSYMA
Maybe this is a bit more simple (some divisions are replaced by multiplications and replace U by 1): [%i*I1*w+(%i*I2)/(C1*w)-(%i*I1)/(C1*w) = 1, %i*I3*w+%i*I2*w+(%i*I3)/(C2*w)-(%i*I2)/(C2*w)-(%i*I2)/(C1*w)+(%i*I1)/(C1*w) = 0, %i*I2*w-(%i*I4)*w-(%i*I3)/(C2*w)+2*(%i*I3)*w+(%i*I2)/(C2*w) = 0, %i*I4*w-(%i*I3)*w+I4 = 0]$ What is remarkable: If you replace the summand 2*(%i*I3)*w by (%i*I3)*w (leave away the constant 2), then Maxima finds the correct solution. If you try to replace other divisions by multiplications,...
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Modified
a comment
on
ticket #4032
on
Maxima -- GPL CAS based on DOE-MACSYMA
Maybe this is a bit more simple (some divisions are replaced by multiplications and replace U by 1): [%i*I1*w+(%i*I2)/(C1*w)-(%i*I1)/(C1*w) = 1, %i*I3*w+%i*I2*w+(%i*I3)/(C2*w)-(%i*I2)/(C2*w)-(%i*I2)/(C1*w)+(%i*I1)/(C1*w) = 0, %i*I2*w-(%i*I4)*w-(%i*I3)/(C2*w)+2*(%i*I3)*w+(%i*I2)/(C2*w) = 0, %i*I4*w-(%i*I3)*w+I4 = 0]$ What is remarkable: If you replace the summand 2*(%i*I3)*w by (%i*I3)*w (leave away the constant 2), then Maxima finds the correct solution. If you try to replace other divisions by multiplications,...
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Modified
a comment
on
ticket #4032
on
Maxima -- GPL CAS based on DOE-MACSYMA
Maybe this is a bit more simple (some divisions are replaced by multiplications and replace U by 1): [%i*I1*w+(%i*I2)/(C1*w)-(%i*I1)/(C1*w) = 1, %i*I3*w+%i*I2*w+(%i*I3)/(C2*w)-(%i*I2)/(C2*w)-(%i*I2)/(C1*w)+(%i*I1)/(C1*w) = 0, %i*I2*w-(%i*I4)*w-(%i*I3)/(C2*w)+2*(%i*I3)*w+(%i*I2)/(C2*w) = 0, %i*I4*w-(%i*I3)*w+I4 = 0]$ What is remarkable: If you replace the summand 2*(%i*I3)*w by (%i*I3)*w (leave away the constant 2), then Maxima finds the correct solution. If you try to replace other divisions by multiplications,...
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Modified
a comment
on
ticket #4032
on
Maxima -- GPL CAS based on DOE-MACSYMA
Maybe this is a bit more simple (some divisions are replaced by multiplications and replace U by 1): [%i*I1*w+(%i*I2)/(C1*w)-(%i*I1)/(C1*w) = 1, %i*I3*w+%i*I2*w+(%i*I3)/(C2*w)-(%i*I2)/(C2*w)-(%i*I2)/(C1*w)+(%i*I1)/(C1*w) = 0, %i*I2*w-(%i*I4)*w-(%i*I3)/(C2*w)+2*(%i*I3)*w+(%i*I2)/(C2*w) = 0, %i*I4*w-(%i*I3)*w+I4 = 0]$ What is remarkable: If you replace the summand 2*(%i*I3)*w by (%i*I3)*w (leave away the constant 2), then Maxima finds the correct solution. If you try to replace other divisions by multiplications,...
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Modified
a comment
on
ticket #4032
on
Maxima -- GPL CAS based on DOE-MACSYMA
Maybe this is a bit more simple (some divisions are replaced by multiplications and replace U by 1): [%i*I1*w+(%i*I2)/(C1*w)-(%i*I1)/(C1*w) = 1, %i*I3*w+%i*I2*w+(%i*I3)/(C2*w)-(%i*I2)/(C2*w)-(%i*I2)/(C1*w)+(%i*I1)/(C1*w) = 0, %i*I2*w-(%i*I4)*w-(%i*I3)/(C2*w)+2*(%i*I3)*w+(%i*I2)/(C2*w) = 0, %i*I4*w-(%i*I3)*w+I4 = 0]$ What is remarkable: If you replace the summand 2*(%i*I3)*w by (%i*I3)*w (leave away the constant 2), then Maxima finds the correct solution. If you try to replace other divisions by multiplications,...
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Modified
a comment
on
ticket #4032
on
Maxima -- GPL CAS based on DOE-MACSYMA
Maybe this is a bit more simple (some divisions are replaced by multiplications and replace U by 1): [%i*I1*w+(%i*I2)/(C1*w)-(%i*I1)/(C1*w) = 1, %i*I3*w+%i*I2*w+(%i*I3)/(C2*w)-(%i*I2)/(C2*w)-(%i*I2)/(C1*w)+(%i*I1)/(C1*w) = 0, %i*I2*w-(%i*I4)*w-(%i*I3)/(C2*w)+2*(%i*I3)*w+(%i*I2)/(C2*w) = 0, %i*I4*w-(%i*I3)*w+I4 = 0]$ What is remarkable: If you replace the summand 2*(%i*I3)*w by (%i*I3)*w (leave away the constant 2), then Maxima finds the correct solution. If you try to replace other divisions by multiplications,...
Personal Data
- Username:
- fkoenigstein
- Joined:
- 2021-04-06 19:20:52
Projects
This is a list of open source software projects that Florian Königstein is associated with:
- Hugin++ a fork of the Hugin project with a fast geometric optimizer Last Updated:
- fastPTOptimizer a fork of the Panorama Tools / libpano13 with a fast PTOptimizer Last Updated:
