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#1082 Taylor polynomials of Bessel functions

closed
nobody
5
2007-01-28
2007-01-22
No

Bessel_j(0,x) is analytic at 0 yet

(%i1) taylor(bessel_j(0,x),x,0,2);
`taylor' encountered an unfamiliar singularity in:

Taylor has no problem expanding bessel_j at 1:

(%i2) taylor(bessel_j(0,x),x,1,2);
(%o2) < junk deleted>

I think the problem with the expansion at zero is
the derivative of bessel_j(0,x) is

(%i3) diff(bessel_j(0,x),x,2);
(%o3) bessel_j(1,x)/x-bessel_j(0,x)

Trying to evaluate this at zero causes problems.

Discussion

  • Barton Willis

    Barton Willis - 2007-01-28

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    Fixed in bessel.lisp CVS r 1.39

     
  • Barton Willis

    Barton Willis - 2007-01-28
    • status: open --> closed
     

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