Re: [Xmpppy-devel] how to log out of a chat room?

[Yann L. <as...@la...>]

On 12/21/2010 06:00 PM, Bryan Oakley wrote:
> I've got a simple client working that connects to a group chat. Now I
> want to implement the ability to set the status to 'away' and/or log
> out of the server.
>
> My first attempts don't seem to work -- if I call the disconnect()
> method on the client that works, but then I'm not able to reconnect.
> This makes me wonder if there's a more proper way to leave a chatroom.
>
> My initialization code looks like this:
>
>      self.client = xmpp.Client(jid.getdomain(), debug=[])
>      self.client.connect()
>      self.client.auth(jid.getNode(), password)
>      self.client.sendpresence("%s/%s" % (room, nick))
>
> That all works great and I'm able to chat with people in the room.
> What must I do to log out of that room (ie: set my status to 'away'),
> yet be able to log back in later?

To log out from a room (and not receive messages from the room) you just 
have to send an unavailable presence.

You should read XEP-0045 which explains the groupchat (MUC) protocol in 
detail.