Re: [Xmpppy-devel] Bot with Socket as input

[Norman R. <no...@ra...>]

On Tue, Aug 31, 2010 at 7:02 AM, Bino Oetomo <bi...@in...>wrote:

> Dear All.
>
> I play with JabberBot from your example.
> I try to make this bot do other thing than just replaying the caller.
>
> Now .. I need to expand this bot to also listen to a TCP-Port
>
> I adopt the socket server from  example  20.17.4.3  of
> <http://docs.python.org/library/socketserver.html>
> http://docs.python.org/library/socketserver.html
>
> what i did is :
> 1. in jabberbot.py
> at the bottom, I add
> ----START----
> class ThreadedTCPRequestHandler(SocketServer.BaseRequestHandler):
>
>    def handle(self):
>        data = self.request.recv(1024)
>        cur_thread = threading.currentThread()
>        response = "%s: %s" % (cur_thread.getName(), data)
>        #self.request.send(response)
>
>         #Lets try to FORWARD data incoming via TCP port to others at
> the XMPP side
>        JabberBot.send('bi...@ja...', data)
>

change this to bot.send.  It needs an instance of JabberBot, not the class.


>
> class ThreadedTCPServer(SocketServer.ThreadingMixIn,
> SocketServer.TCPServer):
>    pass
> ----STOP-----
>
> 2. in broadcast.py
> Inside --> class BroadcastingJabberBot
> at the bottom part of --> def __init__( self, jid, password, res = None):
> I add
> ---START----
>    HOST, PORT = "localhost", 50008
>
>    server = ThreadedTCPServer((HOST, PORT), ThreadedTCPRequestHandler)
>    ip, port = server.server_address
>
>    # Start a thread with the server -- that thread will then start one
>    # more thread for each request
>    server_thread = threading.Thread(target=server.serve_forever)
>    # Exit the server thread when the main thread terminates
>    server_thread.setDaemon(False)
>    server_thread.start()
>    print "Server loop running in thread:", server_thread.getName()
>
>    #-------End of socket server
>
> ----STOP-----
>
> I try to run the broadcast.py .. looks fine
>
> Next, from another shell .. I try to do --> bino@erp:~/Documents$ echo
> "it's me" |nc 127.0.0.1 50008
>
> At the bot shell , I got this error :
> -----START-----
> Exception happened during processing of request from ('127.0.0.1', 51188)
> Traceback (most recent call last):
>  File "/usr/lib/python2.6/SocketServer.py", line 558, in
> process_request_thread
>    self.finish_request(request, client_address)
>  File "/usr/lib/python2.6/SocketServer.py", line 320, in finish_request
>    self.RequestHandlerClass(request, client_address, self)
>  File "/usr/lib/python2.6/SocketServer.py", line 615, in __init__
>    self.handle()
>  File "/home/bino/Documents/iwic/kode/jb01/jabberbot.py", line 506, in
> handle
>    JabberBot.send('bi...@ja...', data)
> TypeError: unbound method send() must be called with JabberBot instance
> as first argument (got str instance instead)
> ------STOP------
>
> So , Kindly please tell me what I have to do to fix this problem.
>
>
> Sincerely
> -bino-
>
>
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-- 
- Norman Rasmussen
 - Email: no...@ra...
 - Home page: http://norman.rasmussen.co.za/