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Re: [Xmpppy-devel] Message are not arriving to a MUC
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From: Norman R. <no...@ra...> - 2010-05-31 13:53:53
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You must call cl.Process(<timeout>) as part of your loop, so that incoming
messages are processed. You can do this instead of your time.sleep
On Mon, May 31, 2010 at 2:16 PM, Cyril LAVIER
<cla...@lt...<clavier%2Bx...@lt...>
> wrote:
> Hi.
>
> I'm coding a simple jabber bot using xmpppy, and after some hours, it
> stops sending messages.
>
> The bot is quite silly, it simply reads a file, and sending the content
> to a muc.
>
> The main problem is, after some hours of running.
>
> I added a "wake up" send every minute, it sends a blank message (like I
> saw in some old messages on the mailing list), but it always do the same
> problem.
>
> Here is the main loop, which reads the file, sends the message in the
> file, and sends a "wake up" message every minute.
>
> cl is a client created using
> "cl=xmpp.client.Client(jid.getDomain(),debug=['always'])"
>
> conference.room is a variable containing the conference room which will
> receive the message.
>
> jabber.jid is the variable containing the complete JID of the user to
> connect.
>
> Here is the part of the code containing the loop which reads the file,
> sends the message in the file, and sends a "wake up" message every minute.
>
> _____________________________
>
> jid=xmpp.protocol.JID(jabber.jid)
> cl=xmpp.client.Client(jid.getDomain(),debug=['always'])
>
> cl.connect()
> cl.auth(jid.getNode(), jabber.jid_password)
> cl.sendInitPresence()
>
> presenceto=conference.room+"/"+conference.username
> presence = xmpp.protocol.Presence(to=presenceto)
> presence.setTag('x',namespace =
> xmpp.protocol.NS_MUC).setTagData('password',conference.room_password)
> cl.send(presence)
>
> mtime = os.stat("/var/cache/mnb_server")[ST_MTIME]
> timer=time.time()
> n=1
>
> while n==1:
> readmtime = os.stat(CACHEFILE)[ST_MTIME]
> if not readmtime == mtime:
> f = open(CACHEFILE, "r")
> readl = f.readline()
> if readl.strip() == "____exit____":
> n=2
> else:
>
> tosend=xmpp.Message(to=conference.room,typ='groupchat',body=readl.strip())
> id=cl.send(tosend)
> open(LOGFILE,
> "a+").write(time.strftime("[%d/%m/%Y - %H:%M:%S]")+"Message #"+str(id)+"
> sent\n")
> mtime = readmtime
> f.close()
> if time.time() > timer + 60:
> idw = cl.send(xmpp.Message())
> open(LOGFILE,
> "a+").write(time.strftime("[%d/%m/%Y - %H:%M:%S]")+"Wake Up
> #"+str(idw)+"\n")
> timer=time.time()
> time.sleep(0.25)
>
> ______________________
>
> In the debug prints, I see the "wake up" messages like this "DEBUG:
> socket sent <message id="1511" />"
>
> And I see the regular messages like this (here, I simply send the
> current date) : "DEBUG: socket sent <message
> to="conferenceroom@conferenceserver" type="groupchat"
> id="1513"><body>Fri May 28 08:53:39 GMT 2010</body></message>"
>
> I set the ejabberd2 server logs to debug, and when the message do not
> arrive in the conference room, they are not displayed in the server logs.
>
> I hope somebody will find an answer to this issue.
>
> Thanks.
>
> --
> Cyril LAVIER | Systems Administrator | LTU Technologies
> 132 Rue de Rivoli - 75001 Paris France
> (tel) +33 (0)1 53 43 01 71 | (mail) cl...@lt...
> LTU technologies - Making Sense of Visual Content | www.LTUtech.com
>
>
>
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>
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>
--
- Norman Rasmussen
- Email: no...@ra...
- Home page: http://norman.rasmussen.co.za/
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