RE: [xmljs-users] Re-ordering XML data...

[Eljon G. <eg...@re...>]

In the example below, the function would be moveSectionUp() or moveSectionD=
own().  Those functions call updateNode(), which is I function I wrote to f=
ind the node and use tNode.getFirstChild().setNodeValue(tValue), which actu=
ally resets the order of the section.  I think your idea of re-ordering the=
 nodelist is something I had not considered but should be possible once I t=
hink it out....Thanks for the inspiration...

So far i have come up with....This function would be called right before I =
save the XML object to the hidden form field.


function reOrderNodes(){
 // Re-order the nodes so that the XML document accurately reflects the cha=
nges made
 var tSections =3D pageRoot.getElementsByTagName(sectionElement);  // secti=
onElement =3D 'section'
 var tTempObj =3D null;  // used to temporary swap nodes
 var i =3D 0;
=20
 // First do sections
  tCurrentSection =3D pageRoot.getElementsByTagName(sectionElement).item(i)=
;
  tCurrentSectionOrder =3D tCurrentSection.getElementsByTagName(orderElemen=
t).item(i);  // orderElement =3D 'orderNumber'
=20
  while(tCurrentSection.getNextSibling() !=3D null) {
 =20
   tNextSection =3D pageRoot.getElementsByTagName(sectionElement).item(i+1)=
;
   tNextSectionOrder =3D tNextSection.getElementsByTagName(orderElement).it=
em(0);
    =20
   // if current section order is greater than next section swap
   if(tCurrentSectionOrder.getFirstChild().getNodeValue() > tNextSectionOrd=
er.getFirstChild().getNodeValue()) {
    tTempObj =3D tCurrentSection;
    tCurrentSection =3D tNextSection;
    tNextSection =3D tTempObj;
   } else {
    break;
   }
  =20
   tCurrentSection =3D pageRoot.getElementsByTagName(sectionElement).item(i=
);
   i++;
  }
}=20

Let me know if I am now in the right direction...Thanks...

P.S.  I had plans to work alittle this weekend on this but I might not...Su=
per Bowl is in town...Party on!!!!!!!!!!!!!

Eljon Greene
CE Software Engineer
877.394.5644 \\ main
904.567.2127 \\ direct
eg...@re...
www.recruitmax.com




From: David Joham
Sent: Fri 2/4/2005 5:53 PM
To: Eljon Greene; xml...@li...
Subject: Re: [xmljs-users] Re-ordering XML data...


Can you do a quick example (just the XML below and how you're trying to man=
ipulate it) so I can
take a look this weekend? I know the XPATH stuff in xmljs is pretty basic a=
nd probably doesn't
support what you're looking for, but it may be possible to enhance it to su=
pport what you're
looking for. At the very least, it should be easy to create a function that=
 will reorder a
nodelist in whatever way you're looking for...

David

--- Eljon Greene <eg...@re...> wrote:

> Hi,
>=20
> This is my last hurdle to overcome (I think) in using XML and the xmlJS l=
ibrary.  I use this
> technology to allow users to control the layout (order, active/inactive, =
labeling) of pages in
> our application.  However the ordering is based on an <orderNumber> eleme=
nt I created by it does
> not change the "position" of the <section> in the XML file.  My question =
is there a way to
> re-order elements?  I can only display the elements by using the XPath po=
sition() function.=20
> Here is the way it works now and the desired result:
>=20
> How it looks now:
>=20
>=20
> <section>
> <id>1</id>
> <name>My Section</name>
> <orderNumber>02</orderNumber>
> <active>Yes</active>
> <locked>Yes</locked>
> </section>
> <section>
> <id>2</id>
> <name>My Other Section</name>
> <orderNumber>01</orderNumber>
> <active>Yes</active>
> <locked>Yes</locked>
> </section>
> The desired results:
>=20
> <section>
> <id>2</id>
> <name>My Other Section</name>
> <orderNumber>01</orderNumber>
> <active>Yes</active>
> <locked>Yes</locked>
> </section>
> <section>
> <id>1</id>
> <name>My Section</name>
> <orderNumber>02</orderNumber>
> <active>Yes</active>
> <locked>Yes</locked>
> </section>
>=20
> Thanks.
>=20
> Eljon Greene
> CE Software Engineer
> 877.394.5644 \\ main
> 904.567.2127 \\ direct
> eg...@re...
> www.recruitmax.com
>=20