wxperl-users

Re: [wxperl-users] RE: RE: RE: Perl 5.8 (Marc)

[Mattia B. <mb...@ds...>]

> Marc,
> 
>   Using the UNIVERSAL::isa it works! I get 1 or undef for the type. Thanks
> for the help!
Don't use UNIVERSAL::isa, its use is discouraged; use $obj->isa( 'Wx::Foo' );

Regards
Mattia

RE: [wxperl-users] RE: RE: RE: Perl 5.8 (Marc)

[Marc M. A. <mm...@Do...>]

> Don't use UNIVERSAL::isa, its use is discouraged

Not arguing with you, but that's a new one on me.  What's your source?

I checked some in the Perl 5.8 doc and I did notice that:

	use	UNIVERSAL qw(isa);

(which I use a lot and have recommended, oops) is discouraged in favor of:

	*isa = \&UNIVERSAL::isa;

Of course, in true Perl style, the same manual page actually uses the
discouraged form in an example!

mma

[wxperl-users] Re: Perl 5.8 (Marc)

[Mattia B. <mb...@ds...>]

> > Don't use UNIVERSAL::isa, its use is discouraged
> 
> Not arguing with you, but that's a new one on me.  What's your source?
IIRC perl5-porters

> I checked some in the Perl 5.8 doc and I did notice that:
> 
> 	use	UNIVERSAL qw(isa);
They surely talked about that. I probably remembered incorrectly that
using UNIVERSAL::isa was discouraged.

> (which I use a lot and have recommended, oops) is discouraged in favor of:
Me too...

> 	*isa = \&UNIVERSAL::isa;
This has a minor problem.
The problem is that some module may decide to override ->isa to make objects
appear to be in some class they are not blessed into. Using UNIVERSAL::isa
breaks that. Of course few modules actually do that so this is a minor problem.

Sorry for the confusion
Mattia