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From: <luc...@co...> - 2007-09-24 10:21:48
|
Hi, I'd like to know if the java service wrapper has any built-in method to run a command when the service is stopped or just before staring it, for example, clean up lock files and stuff like that. Thanks in advance, Lucas Vieites ---------------------------------------------------------------- This message was sent using IMP, the Internet Messaging Program. |
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From: Dittmar G. <gr...@if...> - 2007-09-24 06:37:39
|
Hi Leif Mortenson, First of all, thank you for the good product. We are very satisfied and = we want to go on using the wrapper (and we have given an donation ;-)). We are planning to test our application on a 64Bit Windows operating = system and currently struggle with the 64bit version of the wrapper. I would be very happy if you could bring some light in the dark ;-) by = anwering my questions. 1) I can not find a binary version for the 64 Bit version. 2) I see several questions from other developers who have the same = problem but no very clear answer or different suggestions. 3) I can not find a concluding information by Tanuki about this task. = Ok, I have the list of supported platforms, that does not include the 64Bit Windows platform... What I need to know: - Is the binary version somewhere available? - If not, can we expect such a version and if we can expect it, when can = we expect it? - Is there an other way (build the version by ourselves) to get the = 64Bit wrapper running on Windows64? - Do we have to look for an other tool, because we can not expect a = solution in a acceptable time frame? Thank you for a explanation, that clarifies the questions all around = this task. Best Regards, Dittmar Gross Manager arctic Technology -------------------------------------------------------------------------= ------------------------ i:FAO Group Clemensstrasse 9, 60487 Frankfurt am Main, Germany Tel +49 (69) = 7680-5341, Fax +49 (69) 7680-5100, eMail gr...@if..., www.cytric.info=20 i:FAO Group GmbH Sitz in Frankfurt am Main Eingetragen beim Amtsgericht Frankfurt am Main, HRB 73600 Gesch=E4ftsf=FChrer: Louis Arnitz, Karin Froese=20 Diese Mitteilung ist nur f=FCr den Empf=E4nger bestimmt. Wenn Sie nicht = der bestimmungsgem=E4=DFe Empf=E4nger sind, werden Sie hiermit darauf hingewiesen, da=DF jede Nutzung, Vervielf=E4ltigung oder Verbreitung = dieser eMail, auch in Ausz=FCgen, streng untersagt ist. Bitte informieren Sie den Absender durch R=FCcksendung der eMail und l=F6schen = Sie diese aus Ihrem System. Diese eMail stellt weder ein Vertragsangebot noch eine Vertragserg=E4nzung oder -annahme dar, es sei = denn, sie ist ausdr=FCcklich oder eindeutig derart bezeichnet. Diese eMail stellt auch keine Zustimmung zur Verwendung der hierin = enthaltenen Angaben f=FCr Zwecke des Direktmarketing oder zur Weitergabe von Daten an Dritte dar. To view the disclaimer text in other languages, click here: www.ifao.net/disclaimer |
|
From: Toadie <toa...@gm...> - 2007-09-23 17:58:27
|
Hello, I was browsing the download and am not seeing a binary distribution for Solaris 10 64 bit on X86 ? Are there any plans to provide that in the future? |
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From: no s. <mrs...@gm...> - 2007-09-21 14:09:49
|
I'm using JavaWrapper 3.2.3 and the JRE 1.6.0_01. I have an application that is using JIntegra to talk to COM objects on the local machine that is controlling video encoding hardware. If the system is not loaded things seem to run great and I never see crashes. If I load the software so that it's hovering around 100% cpu I eventually (after 7 hours & not always exactly at this time) get crashes. In the wrapper logs I see this: The JVM process terminated due to an uncaught exception: EXCEPTION_ACCESS_VIOLATION (0xc0000005) JVM exited unexpectedly. Dr Watson shows this: Application exception occurred: App: c:\ipe\mvcp\javawrapper\bin\wrapper.exe (pid=2952) When: 5/1/2007 @ 17:28:49.263 Exception number: c0000005 (access violation) *----> System Information <----* Computer Name: PROXYCT...... User Name: ipv..... Terminal Session Id: 1 Number of Processors: 4 Processor Type: x86 Family 15 Model 4 Stepping 3 Windows Version: 5.2 Current Build: 3790 Service Pack: 1 Current Type: Multiprocessor Free Registered Organization: TBS Registered Owner: TBS *----> Task List <----* 0 System Process 4 System 388 smss.exe 616 csrss.exe 704 winlogon.exe 764 services.exe 776 lsass.exe 988 svchost.exe 1060 svchost.exe 1128 svchost.exe 1196 svchost.exe 1252 svchost.exe 1364 ccSetMgr.exe 1428 ccEvtMgr.exe 864 spoolsv.exe 996 msdtc.exe 1644 vcagent.exe 1664 DefWatch.exe 1692 svchost.exe 1756 svchost.exe 1792 SavRoam.exe 1956 sntlkeyssrvr.exe 1972 spnsrvnt.exe 2000 snmp.exe 2032 snmptrap.exe 464 SVBootService.exe 480 Rtvscan.exe 516 smhstart.exe 580 cpqnimgt.exe 2152 hpsmhd.exe 2184 CpqRcmc.exe 2196 cqmgserv.exe 2240 cqmgstor.exe 2300 sysdown.exe 2420 cqmghost.exe 2464 wmiprvse.exe 2512 svchost.exe 2916 rotatelogs.exe 2924 rotatelogs.exe 2964 hpsmhd.exe 3068 rotatelogs.exe 3076 rotatelogs.exe 2740 wmiprvse.exe 2340 logon.scr 2960 csrss.exe 624 winlogon.exe 1708 rdpclip.exe 3164 Explorer.EXE 2748 cpqteam.exe 2592 ccApp.exe 3128 oobechk.exe 1832 mshta.exe 5128 cmd.exe 5136 bash.exe 5976 csrss.exe 5384 winlogon.exe 6052 rdpclip.exe 4192 Explorer.EXE 3144 cpqteam.exe 5820 ccApp.exe 5824 oobechk.exe 5468 mshta.exe 2624 mmc.exe 856 mmc.exe 5484 bash.exe 5376 cmd.exe 2952 wrapper.exe 576 drwtsn32.exe *----> Module List <----* 0000000000400000 - 0000000000435000: c:\ipe\mvcp\javawrapper\bin\wrapper.exe 0000000071bb0000 - 0000000071bb9000: C:\WINDOWS\system32\WSOCK32.dll 0000000071bf0000 - 0000000071bf8000: C:\WINDOWS\system32\WS2HELP.dll 0000000071c00000 - 0000000071c17000: C:\WINDOWS\system32\WS2_32.dll 0000000077380000 - 0000000077412000: C:\WINDOWS\system32\USER32.dll 0000000077ba0000 - 0000000077bfa000: C:\WINDOWS\system32\msvcrt.dll 0000000077c00000 - 0000000077c49000: C:\WINDOWS\system32\GDI32.dll 0000000077c50000 - 0000000077cef000: C:\WINDOWS\system32\RPCRT4.dll 0000000077da0000 - 0000000077df2000: C:\WINDOWS\system32\SHLWAPI.dll 0000000077e40000 - 0000000077f42000: C:\WINDOWS\system32\kernel32.dll 0000000077f50000 - 0000000077fec000: C:\WINDOWS\system32\ADVAPI32.dll 000000007c800000 - 000000007c8c0000: C:\WINDOWS\system32\ntdll.dll *----> State Dump for Thread Id 0x15d0 <----* eax=01c78c37 ebx=ffff0000 ecx=bb40e508 edx=b34fdbe6 esi=00000000 edi=bb40e64e eip=77e41fb5 esp=0012ff94 ebp=0012ff94 iopl=0 nv up ei pl zr na po nc cs=001b ss=0023 ds=0023 es=0023 fs=003b gs=0000 efl=00010246 *** ERROR: Symbol file could not be found. Defaulted to export symbols for C:\WINDOWS\system32\kernel32.dll - function: kernel32!GetSystemTimeAsFileTime 77e41f99 90 nop kernel32!GetSystemTimeAsFileTime: 77e41f9a 8bff mov edi,edi 77e41f9c 55 push ebp 77e41f9d 8bec mov ebp,esp 77e41f9f a11800fe7f mov eax,[SharedUserData+0x18 (7ffe0018)] 77e41fa4 8b151400fe7f mov edx,[SharedUserData+0x14 (7ffe0014)] 77e41faa 3b051c00fe7f cmp eax,[SharedUserData+0x1c (7ffe001c)] 77e41fb0 75ed jnz kernel32!GetSystemTimeAsFileTime+0x5 (77e41f9f) 77e41fb2 8b4d08 mov ecx,[ebp+0x8] FAULT ->77e41fb5 8911 mov [ecx],edx ds:0023:bb40e508=???????? 77e41fb7 894104 mov [ecx+0x4],eax 77e41fba 5d pop ebp 77e41fbb c20400 ret 0x4 77e41fbe 90 nop 77e41fbf 90 nop 77e41fc0 90 nop 77e41fc1 90 nop 77e41fc2 90 nop kernel32!VirtualProtect: 77e41fc3 8bff mov edi,edi *----> Stack Back Trace <----* *** ERROR: Module load completed but symbols could not be loaded for c:\ipe\mvcp\javawrapper\bin\wrapper.exe ChildEBP RetAddr Args to Child WARNING: Stack unwind information not available. Following frames may be wrong. 0012ff94 0041b080 bb40e508 00000000 00000000 kernel32!GetSystemTimeAsFileTime+0x1b 0012ffbd e500413c 0077e523 00000000 00000000 wrapper+0x1b080 590012ff 00000000 00000000 00000000 00000000 0xe500413c *----> Raw Stack Dump <----* 000000000012ff94 bd ff 12 00 80 b0 41 00 - 08 e5 40 bb 00 00 00 00 ......A...@..... 000000000012ffa4 00 00 00 00 00 f0 fd 7f - 00 00 00 00 74 1e 82 7c ............t..| 000000000012ffb4 00 00 00 00 00 00 00 00 - f0 ff 12 00 59 3c 41 00 ............Y<A. 000000000012ffc4 e5 23 e5 77 00 00 00 00 - 00 00 00 00 00 f0 fd 7f .#.w............ 000000000012ffd4 05 00 00 c0 c8 ff 12 00 - c0 fb 12 00 ff ff ff ff ................ 000000000012ffe4 d0 b7 e6 77 f0 23 e5 77 - 00 00 00 00 00 00 00 00 ...w.#.w........ 000000000012fff4 00 00 00 00 54 3c 41 00 - 00 00 00 00 41 63 74 78 ....T<A.....Actx 0000000000130004 20 00 00 00 01 00 00 00 - 38 4f 00 00 24 01 00 00 .......8O..$... 0000000000130014 00 00 00 00 20 00 00 00 - 00 00 00 00 14 00 00 00 .... ........... 0000000000130024 01 00 00 00 0a 00 00 00 - 34 00 00 00 b4 01 00 00 ........4....... 0000000000130034 01 00 00 00 00 00 00 00 - 00 00 00 00 00 00 00 00 ................ 0000000000130044 00 00 00 00 00 00 00 00 - 02 00 00 00 00 00 00 00 ................ 0000000000130054 00 00 00 00 00 00 00 00 - 14 03 00 00 9c 01 00 00 ................ 0000000000130064 00 00 00 00 5b 49 59 2d - b0 04 00 00 32 00 00 00 ....[IY-....2... 0000000000130074 e4 04 00 00 d2 02 00 00 - 00 00 00 00 ba 71 32 f3 .............q2. 0000000000130084 b8 07 00 00 4a 00 00 00 - 04 08 00 00 f6 02 00 00 ....J........... 0000000000130094 00 00 00 00 cd ea ce 32 - fc 0a 00 00 42 00 00 00 .......2....B... 00000000001300a4 40 0b 00 00 08 03 00 00 - 00 00 00 00 79 e8 3c e2 @...........y.<. 00000000001300b4 48 0e 00 00 32 00 00 00 - 7c 0e 00 00 d2 02 00 00 H...2...|....... 00000000001300c4 00 00 00 00 e4 02 02 83 - 50 11 00 00 46 00 00 00 ........P...F... |
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From: Hubert F. <Hub...@ab...> - 2007-09-21 11:16:29
|
Hi, wrapper.shutdown.timeout=3D10 wrapper.ping.timeout=3D30 I have a service that does not respond in time to my shutdown request. The = stop is received and acknowledged, but the service does not exit in time. My shutdown timeout of 10 seconds is ignored, because wrapperUpdateJavaStat= eTimeout() does not take it, if there is already another timeout set which = is longer. This is normally the case, if you use default wrapper.ping.timeout, which = is 30 seconds.=20 Does anybody have a clever idea, how to solve this without destroying some = wrapper internal logic?=20 hub |
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From: hlr fa <hl...@ya...> - 2007-09-20 15:29:09
|
Hi all,=0AI'm a beginner with this useful tool named wrapper...=0AI have a =
little question : I have a Java application (in reality, it's a web app run=
under Tomcat which is run by wrapper). For some reason, I want to run this=
Java application with AspectJ instead of the classic "java" program.=0AFor=
that, I've set the parameter "wrapper.java.command" to "C:/aspectj1.5/bin/=
aj.bat"=0AUnfortunately, it doesn't work, I got some error, like : =0Ajava.=
lang.NoClassDefFoundError: C:/tools/tomcat/5/0/28/common/endorsed=0A=0AIn f=
act, I've set the parameter "wrapper.java.additional.1" like this=0Awrapper=
.java.additional.1=3D-Djava.endorsed.dirs=3D"C:/tools/tomcat/5.0.28/common/=
endorsed"=0A=0AWhen I try to trace the parameters passed to the "aj.bat" co=
mmand, I see that the second "=3D" was replaced by a blank (" "), so my com=
mand seems like this :=0A"C:/aspectj1.5/bin/aj.bat" -Djava.endorsed.dirs "C=
:/tools/tomcat/5.0.28/common/endorsed" ....=0A=0AHow to keep the second "=
=3D" ?=0AIs wrapper compatible to AspectJ program ?=0A=0AThanks=0A=0A=0A=0A=
=0A=0A=0A ____________________________________________________________=
_________________ =0ANe gardez plus qu'une seule adresse mail ! Copiez vos =
mails vers Yahoo! Mail |
|
From: Jerry B. <sy...@ya...> - 2007-09-16 02:51:42
|
Never mind. Syntax error. Rule of thumb is you can't
see your mistakes until the moment you tell someone
else you have a problem. Thanks for considering
anyway.
jromeo.
Note: forwarded message attached.
____________________________________________________________________________________
Fussy? Opinionated? Impossible to please? Perfect. Join Yahoo!'s user panel and lay it on us. http://surveylink.yahoo.com/gmrs/yahoo_panel_invite.asp?a=7
|
|
From: Jerry B. <sy...@ya...> - 2007-09-16 02:12:27
|
Hi:
I've configured the JKava Service Wrapper to be able
to run JBoss AS to run as a windows service. Upon
running the batch file, I receive the following
output. I've also inlcuded the wrapper.conf file.
Please have a look and let me know if you can find the
trouble. Thanks!
------- JBoss.bat OUTPUT --------
wrapper | --> Wrapper Started as Console
wrapper | Using tick timer.
wrapperp | server listening on port 32000.
wrapper | Launching a JVM...
wrapper | command:
"wrapper.java.command=C:\Java\jdk1.5.0_12\bin\java"
-Djava.library.path="C:\Java\jboss-4.0.5.GA\lib"
-classpath
"C:\Java\jboss-4.0.5.GA\lib\wrapper.jar;C:\Java\jdk1.5.0_12\lib\tools.jar;C:\Java\jboss-4.0.5.GA\bin\run.jar"
-Dwrapper.key="A13Squo_Um666jVo" -Dwrapper.port=32000
-Dwrapper.jvm.port.min=31000
-Dwrapper.jvm.port.max=31999 -Dwrapper.debug="TRUE"
-Dwrapper.pid=3352 -Dwrapper.version="3.2.3"
-Dwrapper.native_library="wrapper"
-Dwrapper.cpu.timeout="10" -Dwrapper.jvmid=1
org.tanukisoftware.wrapper.WrapperSimpleApp
org.jboss.Main
wrapper | Unable to execute Java command. The system
cannot find the file specified. (0x2)
wrapper |
"wrapper.java.command=C:\Java\jdk1.5.0_12\bin\java"
-Djava.library.path="C:\Java\jboss-4.0.5.GA\lib"
-classpath
"C:\Java\jboss-4.0.5.GA\lib\wrapper.jar;C:\Java\jdk1.5.0_12\lib\tools.jar;C:\Java\jboss-4.0.5.GA\bin\run.jar"
-Dwrapper.key="A13Squo_Um666jVo" -Dwrapper.port=32000
-Dwrapper.jvm.port.min=31000
-Dwrapper.jvm.port.max=31999 -Dwrapper.debug="TRUE"
-Dwrapper.pid=3352 -Dwrapper.version="3.2.3"
-Dwrapper.native_library="wrapper"
-Dwrapper.cpu.timeout="10" -Dwrapper.jvmid=1
org.tanukisoftware.wrapper.WrapperSimpleApp
org.jboss.Main
wrapper | Critical error: wait for JVM process failed
Press any key to continue . . .
------- wrapper.conf --------
#********************************************************************
# Wrapper Properties
#********************************************************************
# Java Application
wrapper.java.command=wrapper.java.command=%JAVA_HOME%\bin\java
# Java Main class. This class must implement the
WrapperListener interface
# or guarantee that the WrapperManager class is
initialized. Helper
# classes are provided to do this for you. See the
Integration section
# of the documentation for details.
wrapper.java.mainclass=org.tanukisoftware.wrapper.WrapperSimpleApp
# Java Classpath (include wrapper.jar) Add class path
elements as
# needed starting from 1
wrapper.java.classpath.1=C:\Java\jboss-4.0.5.GA\lib\wrapper.jar
wrapper.java.classpath.2=%JAVA_HOME%\lib\tools.jar
wrapper.java.classpath.3=C:\Java\jboss-4.0.5.GA\bin\run.jar
# Java Library Path (location of Wrapper.DLL or
libwrapper.so)
wrapper.java.library.path.1=C:\Java\jboss-4.0.5.GA\lib
# Java Additional Parameters
#wrapper.java.additional.1=Dprogram.name=C:\Java\jboss-4.0.5.GA\run.bat
# Initial Java Heap Size (in MB)
#wrapper.java.initmemory=3
# Maximum Java Heap Size (in MB)
#wrapper.java.maxmemory=64
# Application parameters. Add parameters as needed
starting from 1
wrapper.app.parameter.1=org.jboss.Main
#********************************************************************
# Wrapper Logging Properties
#********************************************************************
# Format of output for the console. (See docs for
formats)
wrapper.console.format=PM
# Log Level for console output. (See docs for log
levels)
wrapper.console.loglevel=DEBUG
# Log file to use for wrapper output logging.
wrapper.logfile=..\logs\wrapper.log
# Format of output for the log file. (See docs for
formats)
wrapper.logfile.format=LPTM
# Log Level for log file output. (See docs for log
levels)
wrapper.logfile.loglevel=DEBUG
# Maximum size that the log file will be allowed to
grow to before
# the log is rolled. Size is specified in bytes. The
default value
# of 0, disables log rolling. May abbreviate with
the 'k' (kb) or
# 'm' (mb) suffix. For example: 10m = 10 megabytes.
wrapper.logfile.maxsize=0
# Maximum number of rolled log files which will be
allowed before old
# files are deleted. The default value of 0 implies
no limit.
wrapper.logfile.maxfiles=0
# Log Level for sys\event log output. (See docs for
log levels)
wrapper.syslog.loglevel=NONE
#********************************************************************
# Wrapper Windows Properties
#********************************************************************
# Title to use when running as a console
wrapper.console.title=JBoss Application Server
#********************************************************************
# Wrapper Windows NT\2000\XP Service Properties
#********************************************************************
# WARNING - Do not modify any of these properties when
an application
# using this configuration file has been installed as
a service.
# Please uninstall the service before modifying this
section. The
# service can then be reinstalled.
# Name of the service
wrapper.ntservice.name=JBoss
# Display name of the service
wrapper.ntservice.displayname=JBoss Application Server
# Description of the service
wrapper.ntservice.description=JBoss Application Server
# Service dependencies. Add dependencies as needed
starting from 1
wrapper.ntservice.dependency.1=
# Mode in which the service is installed. AUTO_START
or DEMAND_START
wrapper.ntservice.starttype=AUTO_START
# Allow the service to interact with the desktop.
wrapper.ntservice.interactive=false
____________________________________________________________________________________
Luggage? GPS? Comic books?
Check out fitting gifts for grads at Yahoo! Search
http://search.yahoo.com/search?fr=oni_on_mail&p=graduation+gifts&cs=bz
|
|
From: Leif M. <le...@ta...> - 2007-09-14 01:53:18
|
Mark,
You are correct. That should work for you.
Cheers,
Leif
Mark Leone wrote:
> Leif,
>
> Thanks for your response. I don't know much about Unix shell
> programming, so I didn't check the script. But after reading your post,
> I looked at it, and I think I know enough to say this it does indeed do
> what I was looking for. Probably I didn't explain it very well. I was
> hoping to use the return value from invoking the script with the
> argument "status" to tell whether the service was running. I observed
> that it returns 1 when the script is not running, and 0 otherwise. I
> didn't see this documented, so I wondered if it would always be the
> case. But doesn't the following code from the script mean that this is
> indeed the intended behavior, and I can therefore rely on it?
>
> status() {
> getpid
> if [ "X$pid" = "X" ]
> then
> echo "$APP_LONG_NAME is not running."
> exit 1
> else
> echo "$APP_LONG_NAME is running ($pid)."
> exit 0
> fi
> }
>
> I prefer this approach to checking for the presence of the pid file,
> since, as you pointed out, the script ensures not only that a process is
> running with a pid equal to the pid in the pid file, but also that that
> process is the wrapper process.
>
> -Mark
>
> Leif Mortenson wrote:
>
>> Mark,
>> The shell script on UNIX does not currently work that way. It would
>> be easy to modify the shell script to do so however when it is called
>> with the "status" command.
>>
>> As an alternative, would checking for the pid file work for you? The
>> Wrapper can be configured to output a pid file on startup. This is
>> the norm when using the provided shell script on UNIX but needs
>> to be set on Windows: wrapper.pidfile
>>
>> You can also check for a running JVM with the wrapper.java.pidfile
>> property.
>>
>> If you want more detail on the exact status of the Wrapper or JVM
>> processes, you could also use the wrapper.statusfile and
>> wrapper.java.statusfile properties.
>>
>> See the documentation for all of the above.
>> http://wrapper.tanukisoftware.org/doc/english/properties.html
>>
>> Just so you are aware, the pid file will always be deleted if the
>> Wrapper shuts down normally, but it could be left around if the
>> Wrapper were to crash or be killed with kill -9. Same if the OS
>> itself were to crash. The shell script works around these cases
>> by actually looking for the process located within the pid file.
>>
>> Cheers,
>> Leif
>>
>> Mark Leone wrote:
>>
>>> I'm using Runtime.exec() Java method to execute the Unix script that
>>> was re-named to the name of my app. Thus I use
>>>
>>> String[] cmd = new String[]{myPath + "/myAppName" ,"status"};
>>> Process process = Runtime.getRuntime().exec(cmd);
>>>
>>> I can capture the standard output from process, and get a verbal
>>> description of the status of the service. However I'd prefer to get
>>> an integer or byte status, the way it works with Windows (executing
>>> wrapper.exe, not the script). So instead of capturing standard out
>>> from the Process created by exec(), I use
>>>
>>> int result = process.waitFor();
>>>
>>> When I do this, result = 1 if the service is not running, 0 if the
>>> service is running. (If I get the status of executing "wrapper -qs
>>> ../conf/wrapper.conf" as with Windows, I get result = 1 no matter if
>>> the service is up or down.) I don't see this status result documented
>>> anywhere for the Unix script. Is this behavior I can rely on, or
>>> should I parse the standard output from process to determine the
>>> status of the service? I'm trying to avoid the latter, because I'm
>>> having trouble processing the standard output from process when I
>>> invoke exec() from the Event Dispatch Thread, which I need to do.
>>>
>>> -Mark
>>>
>>>
>>
>>
|
|
From: Mark L. <mid...@ve...> - 2007-09-14 01:39:23
|
Leif,
Thanks for your response. I don't know much about Unix shell
programming, so I didn't check the script. But after reading your post,
I looked at it, and I think I know enough to say this it does indeed do
what I was looking for. Probably I didn't explain it very well. I was
hoping to use the return value from invoking the script with the
argument "status" to tell whether the service was running. I observed
that it returns 1 when the script is not running, and 0 otherwise. I
didn't see this documented, so I wondered if it would always be the
case. But doesn't the following code from the script mean that this is
indeed the intended behavior, and I can therefore rely on it?
status() {
getpid
if [ "X$pid" = "X" ]
then
echo "$APP_LONG_NAME is not running."
exit 1
else
echo "$APP_LONG_NAME is running ($pid)."
exit 0
fi
}
I prefer this approach to checking for the presence of the pid file,
since, as you pointed out, the script ensures not only that a process is
running with a pid equal to the pid in the pid file, but also that that
process is the wrapper process.
-Mark
Leif Mortenson wrote:
> Mark,
> The shell script on UNIX does not currently work that way. It would
> be easy to modify the shell script to do so however when it is called
> with the "status" command.
>
> As an alternative, would checking for the pid file work for you? The
> Wrapper can be configured to output a pid file on startup. This is
> the norm when using the provided shell script on UNIX but needs
> to be set on Windows: wrapper.pidfile
>
> You can also check for a running JVM with the wrapper.java.pidfile
> property.
>
> If you want more detail on the exact status of the Wrapper or JVM
> processes, you could also use the wrapper.statusfile and
> wrapper.java.statusfile properties.
>
> See the documentation for all of the above.
> http://wrapper.tanukisoftware.org/doc/english/properties.html
>
> Just so you are aware, the pid file will always be deleted if the
> Wrapper shuts down normally, but it could be left around if the
> Wrapper were to crash or be killed with kill -9. Same if the OS
> itself were to crash. The shell script works around these cases
> by actually looking for the process located within the pid file.
>
> Cheers,
> Leif
>
> Mark Leone wrote:
>> I'm using Runtime.exec() Java method to execute the Unix script that
>> was re-named to the name of my app. Thus I use
>>
>> String[] cmd = new String[]{myPath + "/myAppName" ,"status"};
>> Process process = Runtime.getRuntime().exec(cmd);
>>
>> I can capture the standard output from process, and get a verbal
>> description of the status of the service. However I'd prefer to get
>> an integer or byte status, the way it works with Windows (executing
>> wrapper.exe, not the script). So instead of capturing standard out
>> from the Process created by exec(), I use
>>
>> int result = process.waitFor();
>>
>> When I do this, result = 1 if the service is not running, 0 if the
>> service is running. (If I get the status of executing "wrapper -qs
>> ../conf/wrapper.conf" as with Windows, I get result = 1 no matter if
>> the service is up or down.) I don't see this status result documented
>> anywhere for the Unix script. Is this behavior I can rely on, or
>> should I parse the standard output from process to determine the
>> status of the service? I'm trying to avoid the latter, because I'm
>> having trouble processing the standard output from process when I
>> invoke exec() from the Event Dispatch Thread, which I need to do.
>>
>> -Mark
>>
>
>
>
|
|
From: Leif M. <le...@ta...> - 2007-09-12 14:47:06
|
Mark, The shell script on UNIX does not currently work that way. It would be easy to modify the shell script to do so however when it is called with the "status" command. As an alternative, would checking for the pid file work for you? The Wrapper can be configured to output a pid file on startup. This is the norm when using the provided shell script on UNIX but needs to be set on Windows: wrapper.pidfile You can also check for a running JVM with the wrapper.java.pidfile property. If you want more detail on the exact status of the Wrapper or JVM processes, you could also use the wrapper.statusfile and wrapper.java.statusfile properties. See the documentation for all of the above. http://wrapper.tanukisoftware.org/doc/english/properties.html Just so you are aware, the pid file will always be deleted if the Wrapper shuts down normally, but it could be left around if the Wrapper were to crash or be killed with kill -9. Same if the OS itself were to crash. The shell script works around these cases by actually looking for the process located within the pid file. Cheers, Leif Mark Leone wrote: > I'm using Runtime.exec() Java method to execute the Unix script that was > re-named to the name of my app. Thus I use > > String[] cmd = new String[]{myPath + "/myAppName" ,"status"}; > Process process = Runtime.getRuntime().exec(cmd); > > I can capture the standard output from process, and get a verbal > description of the status of the service. However I'd prefer to get an > integer or byte status, the way it works with Windows (executing > wrapper.exe, not the script). So instead of capturing standard out from > the Process created by exec(), I use > > int result = process.waitFor(); > > When I do this, result = 1 if the service is not running, 0 if the > service is running. (If I get the status of executing "wrapper -qs > ../conf/wrapper.conf" as with Windows, I get result = 1 no matter if the > service is up or down.) I don't see this status result documented > anywhere for the Unix script. Is this behavior I can rely on, or should > I parse the standard output from process to determine the status of the > service? I'm trying to avoid the latter, because I'm having trouble > processing the standard output from process when I invoke exec() from > the Event Dispatch Thread, which I need to do. > > -Mark > |
|
From: Mark L. <mid...@ve...> - 2007-09-12 01:01:13
|
I'm using Runtime.exec() Java method to execute the Unix script that was
re-named to the name of my app. Thus I use
String[] cmd = new String[]{myPath + "/myAppName" ,"status"};
Process process = Runtime.getRuntime().exec(cmd);
I can capture the standard output from process, and get a verbal
description of the status of the service. However I'd prefer to get an
integer or byte status, the way it works with Windows (executing
wrapper.exe, not the script). So instead of capturing standard out from
the Process created by exec(), I use
int result = process.waitFor();
When I do this, result = 1 if the service is not running, 0 if the
service is running. (If I get the status of executing "wrapper -qs
../conf/wrapper.conf" as with Windows, I get result = 1 no matter if the
service is up or down.) I don't see this status result documented
anywhere for the Unix script. Is this behavior I can rely on, or should
I parse the standard output from process to determine the status of the
service? I'm trying to avoid the latter, because I'm having trouble
processing the standard output from process when I invoke exec() from
the Event Dispatch Thread, which I need to do.
-Mark
|
|
From: Leif M. <le...@ta...> - 2007-09-08 08:23:07
|
Frank, By default, the Wrapper runs as the SYSTEM user. If you want to be running as a specific user, try setting the wrapper.ntservice.account property. Be sure to read the docs: http://wrapper.tanukisoftware.org/doc/english/prop-ntservice-account.html Cheers, Leif Frank F Chiang wrote: > I have a Java program in which I'm calling System.getProperty("user.home"); to get the user's home directory. This would give me something like C:\Users\username (on Vista). > > I've connected it to the wrapper and when I run the App.bat file, everything is still fine, but when I install the program as a service and try to start it in Control Panel -> Administrative Tools -> Services, then it returns an error. In the log that was created, I see that System.getProperty("user.home") suddenly gives C:\ instead of my home directory. > > Does anyone know why this is and how to solve this problem? > > Thanks! |
|
From: Nicolas V. <ni...@va...> - 2007-09-08 06:56:54
|
Le 7 sept. 07 =E0 23:11, Frank F Chiang a =E9crit :
> I have a Java program in which I'm calling System.getProperty=20
> ("user.home"); to get the user's home directory. This would give =20
> me something like C:\Users\username (on Vista).
>
> I've connected it to the wrapper and when I run the App.bat file, =20
> everything is still fine, but when I install the program as a =20
> service and try to start it in Control Panel -> Administrative =20
> Tools -> Services, then it returns an error. In the log that was =20
> created, I see that System.getProperty("user.home") suddenly gives =20
> C:\ instead of my home directory.
>
> Does anyone know why this is and how to solve this problem?
>
> Thanks!
A Windows Service runs by default as SYSTEM user account.
Specify the service to run in a particular user account in the =20
service control panel of Windows.
Regards
Nicolas=
|
|
From: Frank F C. <ff...@ny...> - 2007-09-07 21:11:46
|
I have a Java program in which I'm calling System.getProperty("user.home"); to get the user's home directory. This would give me something like C:\Users\username (on Vista).
I've connected it to the wrapper and when I run the App.bat file, everything is still fine, but when I install the program as a service and try to start it in Control Panel -> Administrative Tools -> Services, then it returns an error. In the log that was created, I see that System.getProperty("user.home") suddenly gives C:\ instead of my home directory.
Does anyone know why this is and how to solve this problem?
Thanks!
|
|
From: Sujatha B. <suj...@td...> - 2007-09-06 14:15:42
|
yes i see all the appenders and the message which i had given in my java fi=
le.
I understand that console output is working fine..but the problem is writin=
g to a file..dont know why it is not working!=20
=20
----- Original Message -----
From: wra...@li... on behalf of Rodrigo Vega=
=20
Sent: Thu, 6/9/2007 14:57
To: wra...@li...
Subject: Re: [Wrapper-user] Log4j with the wrapper=20
=20
=20
I see you are setting the parameter -Dlog4j.debug... so can you see in the
wrapper log file if your appenders, and categories are created?
Rodrigo G. Vega
i411 Argentina
rv...@i4...
Este mensaje es confidencial. Si usted ha recibido este e-mail por error, p=
or
favor comun=EDquenoslo inmediatamente v=EDa e-mail y tenga la amabilidad de
eliminarlo de su sistema; no deber=E1 copiar el mensaje ni divulgar su
contenido a ninguna persona. Muchas gracias.
This message is confidential. If you have received it by mistake please let
us know by e-mail immediately and delete it from your system; you should al=
so
not copy the message nor disclose its contents to anyone. Many thanks.
-----Original Message-----
From: wra...@li... on behalf of Sujatha
Bharathan
Sent: Thu 06/09/2007 10:49
To: wra...@li...
Subject: Re: [Wrapper-user] Log4j with the wrapper
I have simplified my config file and the last line i tried the path till cf=
g
.
But stil the log file is not getting generated.=20
Any other reason you could think of?
----- Original Message -----
From: wra...@li... on behalf of Rodrigo Vega=
=20
Sent: Thu, 6/9/2007 14:39
To: wra...@li...
Subject: Re: [Wrapper-user] Log4j with the wrapper=20
Can you try changing that:
# Java Classpath (include wrapper.jar) Add class path elements as
# needed starting from 1
wrapper.java.classpath.1=3DC:\Program
Files\sb\3rdParty\wrapper-windows\lib\wrapper.jar
wrapper.java.classpath.2=3DC:\Program Files\Java\jdk1.5.0_12\lib\tools.jar
wrapper.java.classpath.3=3DC:\Program Files\sb\lib\jar\sb_Bus_Core.jar
wrapper.java.classpath.4=3DC:\Program
Files\sb\lib\jar\sb_sgPlugin_FileLogger.jar
wrapper.java.classpath.5=3DC:\Program
Files\sb\lib\jar\sb_sgPlugin_JdbcLogger.jar
wrapper.java.classpath.6=3DC:\Program
Files\sb\lib\jar\sb_sgPlugin_VitalSuite.jar
wrapper.java.classpath.7=3DC:\Program
Files\sb\lib\jar\sb_sgPlugin_VoyenceControl.jar
wrapper.java.classpath.8=3DC:\Program Files\sb\lib\jar\sb_voyenceApi.jar
wrapper.java.classpath.9=3DC:\Program Files\sb\3rdParty\jar\log4j.jar
wrapper.java.classpath.10=3DC:\Program Files\sb\lib\jar\sb_util.jar
wrapper.java.classpath.11=3DC:\Program Files\sb\lib\jar\sb_sgFilter_String.=
jar
wrapper.java.classpath.12=3DC:\Program Files\sb\cfg\log4j.properties
to that:
wrapper.java.classpath.1=3DC:\Program
Files\sb\3rdParty\wrapper-windows\lib\wrapper.jar
wrapper.java.classpath.2=3DC:\Program Files\Java\jdk1.5.0_12\lib\tools.jar
wrapper.java.classpath.3=3DC:\Program Files\sb\lib\jar\*.jar
wrapper.java.classpath.4=3DC:\Program Files\sb\3rdParty\jar\log4j.jar
wrapper.java.classpath.5=3DC:\Program Files\sb\cfg\
Pay attention to the last line... where you include the log4j configuration=
.
I remember i had a couple of problems because if you specify a file that is
not a jar then the application doesn't work, but if you specify a directory
all the files in the directory will be in the classpath.
And try to use wild cards to simplify your configuration file.
BTW... My application works in the same way than yours... with a thread. So
it is possible.
Regards!
Rodrigo G. Vega
i411 Argentina
rv...@i4...
Este mensaje es confidencial. Si usted ha recibido este e-mail por error, p=
or
favor comun=EDquenoslo inmediatamente v=EDa e-mail y tenga la amabilidad de
eliminarlo de su sistema; no deber=E1 copiar el mensaje ni divulgar su
contenido a ninguna persona. Muchas gracias.
This message is confidential. If you have received it by mistake please let
us know by e-mail immediately and delete it from your system; you should al=
so
not copy the message nor disclose its contents to anyone. Many thanks.
-----Original Message-----
From: wra...@li... on behalf of Sujatha
Bharathan
Sent: Thu 06/09/2007 10:02
To: wra...@li...
Subject: Re: [Wrapper-user] Log4j with the wrapper
Please find wrapper.conf and log4j.properties file attached.
This is how i am initializing in my java program.
static Logger logger =3D Logger.getRootLogger();
----- Original Message -----
From: wra...@li... on behalf of Rodrigo Vega=
=20
Sent: Thu, 6/9/2007 13:44
To: wra...@li...
Subject: Re: [Wrapper-user] Log4j with the wrapper=20
I have a very similar problem a couple of weeks ago... An the wrapper works
fine.=20
Attach your wrapper.conf and show me how you are initializing your log4j. I=
f
you are loading your log4j.xml from the classpath there are many possible
problems like:
log4j doesn't found the log4j.xml in the classpath
you have multiples log4j.xml in your classpath and is not loading the right
one
etc..
Regards..
Rodrigo G. Vega
i411 Argentina
rv...@i4...
Este mensaje es confidencial. Si usted ha recibido este e-mail por error, p=
or
favor comun=EDquenoslo inmediatamente v=EDa e-mail y tenga la amabilidad de
eliminarlo de su sistema; no deber=E1 copiar el mensaje ni divulgar su
contenido a ninguna persona. Muchas gracias.
This message is confidential. If you have received it by mistake please let
us know by e-mail immediately and delete it from your system; you should al=
so
not copy the message nor disclose its contents to anyone. Many thanks.
-----Original Message-----
From: wra...@li... on behalf of Sujatha
Bharathan
Sent: Thu 06/09/2007 6:01
To: wra...@li...
Subject: [Wrapper-user] Log4j with the wrapper
Hi,
I am using the webservice to create a windows service for my java program. =
I
have configured log4j for seeing hte logging for my java file.
But i see that my log file is not created at all. I see a wrapper.log file
and all my console output appears in the wrapper.log. But i am expecting al=
l
the same in my logfile.
Does the wrapper override any existing configuration for log4j and can writ=
e
only inside the configuration file of the wrapper?
Is there any work around for this?
Thanks
Sujie
-------------------------------------------------------------------------
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|
|
From: Rodrigo V. <rv...@i4...> - 2007-09-06 13:56:46
|
I see you are setting the parameter -Dlog4j.debug... so can you see in =
the
wrapper log file if your appenders, and categories are created?
Rodrigo G. Vega
i411 Argentina
rv...@i4...
=20
Este mensaje es confidencial. Si usted ha recibido este e-mail por =
error, por
favor comun=EDquenoslo inmediatamente v=EDa e-mail y tenga la amabilidad =
de
eliminarlo de su sistema; no deber=E1 copiar el mensaje ni divulgar su
contenido a ninguna persona. Muchas gracias.
=20
This message is confidential. If you have received it by mistake please =
let
us know by e-mail immediately and delete it from your system; you should =
also
not copy the message nor disclose its contents to anyone. Many thanks.
-----Original Message-----
From: wra...@li... on behalf of Sujatha
Bharathan
Sent: Thu 06/09/2007 10:49
To: wra...@li...
Subject: Re: [Wrapper-user] Log4j with the wrapper
=20
I have simplified my config file and the last line i tried the path till =
cfg
.
But stil the log file is not getting generated.=20
=20
Any other reason you could think of?
=20
----- Original Message -----
From: wra...@li... on behalf of Rodrigo =
Vega=20
Sent: Thu, 6/9/2007 14:39
To: wra...@li...
Subject: Re: [Wrapper-user] Log4j with the wrapper=20
=20
=20
Can you try changing that:
# Java Classpath (include wrapper.jar) Add class path elements as
# needed starting from 1
wrapper.java.classpath.1=3DC:\Program
Files\sb\3rdParty\wrapper-windows\lib\wrapper.jar
wrapper.java.classpath.2=3DC:\Program =
Files\Java\jdk1.5.0_12\lib\tools.jar
wrapper.java.classpath.3=3DC:\Program Files\sb\lib\jar\sb_Bus_Core.jar
wrapper.java.classpath.4=3DC:\Program
Files\sb\lib\jar\sb_sgPlugin_FileLogger.jar
wrapper.java.classpath.5=3DC:\Program
Files\sb\lib\jar\sb_sgPlugin_JdbcLogger.jar
wrapper.java.classpath.6=3DC:\Program
Files\sb\lib\jar\sb_sgPlugin_VitalSuite.jar
wrapper.java.classpath.7=3DC:\Program
Files\sb\lib\jar\sb_sgPlugin_VoyenceControl.jar
wrapper.java.classpath.8=3DC:\Program Files\sb\lib\jar\sb_voyenceApi.jar
wrapper.java.classpath.9=3DC:\Program Files\sb\3rdParty\jar\log4j.jar
wrapper.java.classpath.10=3DC:\Program Files\sb\lib\jar\sb_util.jar
wrapper.java.classpath.11=3DC:\Program =
Files\sb\lib\jar\sb_sgFilter_String.jar
wrapper.java.classpath.12=3DC:\Program Files\sb\cfg\log4j.properties
to that:
wrapper.java.classpath.1=3DC:\Program
Files\sb\3rdParty\wrapper-windows\lib\wrapper.jar
wrapper.java.classpath.2=3DC:\Program =
Files\Java\jdk1.5.0_12\lib\tools.jar
wrapper.java.classpath.3=3DC:\Program Files\sb\lib\jar\*.jar
wrapper.java.classpath.4=3DC:\Program Files\sb\3rdParty\jar\log4j.jar
wrapper.java.classpath.5=3DC:\Program Files\sb\cfg\
Pay attention to the last line... where you include the log4j =
configuration.
I remember i had a couple of problems because if you specify a file that =
is
not a jar then the application doesn't work, but if you specify a =
directory
all the files in the directory will be in the classpath.
And try to use wild cards to simplify your configuration file.
BTW... My application works in the same way than yours... with a thread. =
So
it is possible.
Regards!
Rodrigo G. Vega
i411 Argentina
rv...@i4...
Este mensaje es confidencial. Si usted ha recibido este e-mail por =
error, por
favor comun=EDquenoslo inmediatamente v=EDa e-mail y tenga la amabilidad =
de
eliminarlo de su sistema; no deber=E1 copiar el mensaje ni divulgar su
contenido a ninguna persona. Muchas gracias.
This message is confidential. If you have received it by mistake please =
let
us know by e-mail immediately and delete it from your system; you should =
also
not copy the message nor disclose its contents to anyone. Many thanks.
-----Original Message-----
From: wra...@li... on behalf of Sujatha
Bharathan
Sent: Thu 06/09/2007 10:02
To: wra...@li...
Subject: Re: [Wrapper-user] Log4j with the wrapper
Please find wrapper.conf and log4j.properties file attached.
This is how i am initializing in my java program.
static Logger logger =3D Logger.getRootLogger();
----- Original Message -----
From: wra...@li... on behalf of Rodrigo =
Vega=20
Sent: Thu, 6/9/2007 13:44
To: wra...@li...
Subject: Re: [Wrapper-user] Log4j with the wrapper=20
I have a very similar problem a couple of weeks ago... An the wrapper =
works
fine.=20
Attach your wrapper.conf and show me how you are initializing your =
log4j. If
you are loading your log4j.xml from the classpath there are many =
possible
problems like:
log4j doesn't found the log4j.xml in the classpath
you have multiples log4j.xml in your classpath and is not loading the =
right
one
etc..
Regards..
Rodrigo G. Vega
i411 Argentina
rv...@i4...
Este mensaje es confidencial. Si usted ha recibido este e-mail por =
error, por
favor comun=EDquenoslo inmediatamente v=EDa e-mail y tenga la amabilidad =
de
eliminarlo de su sistema; no deber=E1 copiar el mensaje ni divulgar su
contenido a ninguna persona. Muchas gracias.
This message is confidential. If you have received it by mistake please =
let
us know by e-mail immediately and delete it from your system; you should =
also
not copy the message nor disclose its contents to anyone. Many thanks.
-----Original Message-----
From: wra...@li... on behalf of Sujatha
Bharathan
Sent: Thu 06/09/2007 6:01
To: wra...@li...
Subject: [Wrapper-user] Log4j with the wrapper
Hi,
I am using the webservice to create a windows service for my java =
program. I
have configured log4j for seeing hte logging for my java file.
But i see that my log file is not created at all. I see a wrapper.log =
file
and all my console output appears in the wrapper.log. But i am expecting =
all
the same in my logfile.
Does the wrapper override any existing configuration for log4j and can =
write
only inside the configuration file of the wrapper?
Is there any work around for this?
Thanks
Sujie
-------------------------------------------------------------------------=
This SF.net email is sponsored by: Splunk Inc.
Still grepping through log files to find problems? Stop.
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_______________________________________________
Wrapper-user mailing list
Wra...@li...
https://lists.sourceforge.net/lists/listinfo/wrapper-user
|
|
From: Sujatha B. <suj...@td...> - 2007-09-06 13:51:06
|
I have simplified my config file and the last line i tried the path till cf=
g .
But stil the log file is not getting generated.=20
=20
Any other reason you could think of?
=20
----- Original Message -----
From: wra...@li... on behalf of Rodrigo Vega=
=20
Sent: Thu, 6/9/2007 14:39
To: wra...@li...
Subject: Re: [Wrapper-user] Log4j with the wrapper=20
=20
=20
Can you try changing that:
# Java Classpath (include wrapper.jar) Add class path elements as
# needed starting from 1
wrapper.java.classpath.1=3DC:\Program
Files\sb\3rdParty\wrapper-windows\lib\wrapper.jar
wrapper.java.classpath.2=3DC:\Program Files\Java\jdk1.5.0_12\lib\tools.jar
wrapper.java.classpath.3=3DC:\Program Files\sb\lib\jar\sb_Bus_Core.jar
wrapper.java.classpath.4=3DC:\Program
Files\sb\lib\jar\sb_sgPlugin_FileLogger.jar
wrapper.java.classpath.5=3DC:\Program
Files\sb\lib\jar\sb_sgPlugin_JdbcLogger.jar
wrapper.java.classpath.6=3DC:\Program
Files\sb\lib\jar\sb_sgPlugin_VitalSuite.jar
wrapper.java.classpath.7=3DC:\Program
Files\sb\lib\jar\sb_sgPlugin_VoyenceControl.jar
wrapper.java.classpath.8=3DC:\Program Files\sb\lib\jar\sb_voyenceApi.jar
wrapper.java.classpath.9=3DC:\Program Files\sb\3rdParty\jar\log4j.jar
wrapper.java.classpath.10=3DC:\Program Files\sb\lib\jar\sb_util.jar
wrapper.java.classpath.11=3DC:\Program Files\sb\lib\jar\sb_sgFilter_String.=
jar
wrapper.java.classpath.12=3DC:\Program Files\sb\cfg\log4j.properties
to that:
wrapper.java.classpath.1=3DC:\Program
Files\sb\3rdParty\wrapper-windows\lib\wrapper.jar
wrapper.java.classpath.2=3DC:\Program Files\Java\jdk1.5.0_12\lib\tools.jar
wrapper.java.classpath.3=3DC:\Program Files\sb\lib\jar\*.jar
wrapper.java.classpath.4=3DC:\Program Files\sb\3rdParty\jar\log4j.jar
wrapper.java.classpath.5=3DC:\Program Files\sb\cfg\
Pay attention to the last line... where you include the log4j configuration=
.
I remember i had a couple of problems because if you specify a file that is
not a jar then the application doesn't work, but if you specify a directory
all the files in the directory will be in the classpath.
And try to use wild cards to simplify your configuration file.
BTW... My application works in the same way than yours... with a thread. So
it is possible.
Regards!
Rodrigo G. Vega
i411 Argentina
rv...@i4...
Este mensaje es confidencial. Si usted ha recibido este e-mail por error, p=
or
favor comun=EDquenoslo inmediatamente v=EDa e-mail y tenga la amabilidad de
eliminarlo de su sistema; no deber=E1 copiar el mensaje ni divulgar su
contenido a ninguna persona. Muchas gracias.
This message is confidential. If you have received it by mistake please let
us know by e-mail immediately and delete it from your system; you should al=
so
not copy the message nor disclose its contents to anyone. Many thanks.
-----Original Message-----
From: wra...@li... on behalf of Sujatha
Bharathan
Sent: Thu 06/09/2007 10:02
To: wra...@li...
Subject: Re: [Wrapper-user] Log4j with the wrapper
Please find wrapper.conf and log4j.properties file attached.
This is how i am initializing in my java program.
static Logger logger =3D Logger.getRootLogger();
----- Original Message -----
From: wra...@li... on behalf of Rodrigo Vega=
=20
Sent: Thu, 6/9/2007 13:44
To: wra...@li...
Subject: Re: [Wrapper-user] Log4j with the wrapper=20
I have a very similar problem a couple of weeks ago... An the wrapper works
fine.=20
Attach your wrapper.conf and show me how you are initializing your log4j. I=
f
you are loading your log4j.xml from the classpath there are many possible
problems like:
log4j doesn't found the log4j.xml in the classpath
you have multiples log4j.xml in your classpath and is not loading the right
one
etc..
Regards..
Rodrigo G. Vega
i411 Argentina
rv...@i4...
Este mensaje es confidencial. Si usted ha recibido este e-mail por error, p=
or
favor comun=EDquenoslo inmediatamente v=EDa e-mail y tenga la amabilidad de
eliminarlo de su sistema; no deber=E1 copiar el mensaje ni divulgar su
contenido a ninguna persona. Muchas gracias.
This message is confidential. If you have received it by mistake please let
us know by e-mail immediately and delete it from your system; you should al=
so
not copy the message nor disclose its contents to anyone. Many thanks.
-----Original Message-----
From: wra...@li... on behalf of Sujatha
Bharathan
Sent: Thu 06/09/2007 6:01
To: wra...@li...
Subject: [Wrapper-user] Log4j with the wrapper
Hi,
I am using the webservice to create a windows service for my java program. =
I
have configured log4j for seeing hte logging for my java file.
But i see that my log file is not created at all. I see a wrapper.log file
and all my console output appears in the wrapper.log. But i am expecting al=
l
the same in my logfile.
Does the wrapper override any existing configuration for log4j and can writ=
e
only inside the configuration file of the wrapper?
Is there any work around for this?
Thanks
Sujie
|
|
From: Rodrigo V. <rv...@i4...> - 2007-09-06 13:38:58
|
Can you try changing that:
# Java Classpath (include wrapper.jar) Add class path elements as
# needed starting from 1
wrapper.java.classpath.1=3DC:\Program
Files\sb\3rdParty\wrapper-windows\lib\wrapper.jar
wrapper.java.classpath.2=3DC:\Program =
Files\Java\jdk1.5.0_12\lib\tools.jar
wrapper.java.classpath.3=3DC:\Program Files\sb\lib\jar\sb_Bus_Core.jar
wrapper.java.classpath.4=3DC:\Program
Files\sb\lib\jar\sb_sgPlugin_FileLogger.jar
wrapper.java.classpath.5=3DC:\Program
Files\sb\lib\jar\sb_sgPlugin_JdbcLogger.jar
wrapper.java.classpath.6=3DC:\Program
Files\sb\lib\jar\sb_sgPlugin_VitalSuite.jar
wrapper.java.classpath.7=3DC:\Program
Files\sb\lib\jar\sb_sgPlugin_VoyenceControl.jar
wrapper.java.classpath.8=3DC:\Program Files\sb\lib\jar\sb_voyenceApi.jar
wrapper.java.classpath.9=3DC:\Program Files\sb\3rdParty\jar\log4j.jar
wrapper.java.classpath.10=3DC:\Program Files\sb\lib\jar\sb_util.jar
wrapper.java.classpath.11=3DC:\Program =
Files\sb\lib\jar\sb_sgFilter_String.jar
wrapper.java.classpath.12=3DC:\Program Files\sb\cfg\log4j.properties
to that:
wrapper.java.classpath.1=3DC:\Program
Files\sb\3rdParty\wrapper-windows\lib\wrapper.jar
wrapper.java.classpath.2=3DC:\Program =
Files\Java\jdk1.5.0_12\lib\tools.jar
wrapper.java.classpath.3=3DC:\Program Files\sb\lib\jar\*.jar
wrapper.java.classpath.4=3DC:\Program Files\sb\3rdParty\jar\log4j.jar
wrapper.java.classpath.5=3DC:\Program Files\sb\cfg\
Pay attention to the last line... where you include the log4j =
configuration.
I remember i had a couple of problems because if you specify a file that =
is
not a jar then the application doesn't work, but if you specify a =
directory
all the files in the directory will be in the classpath.
And try to use wild cards to simplify your configuration file.
BTW... My application works in the same way than yours... with a thread. =
So
it is possible.
Regards!
Rodrigo G. Vega
i411 Argentina
rv...@i4...
=20
Este mensaje es confidencial. Si usted ha recibido este e-mail por =
error, por
favor comun=EDquenoslo inmediatamente v=EDa e-mail y tenga la amabilidad =
de
eliminarlo de su sistema; no deber=E1 copiar el mensaje ni divulgar su
contenido a ninguna persona. Muchas gracias.
=20
This message is confidential. If you have received it by mistake please =
let
us know by e-mail immediately and delete it from your system; you should =
also
not copy the message nor disclose its contents to anyone. Many thanks.
-----Original Message-----
From: wra...@li... on behalf of Sujatha
Bharathan
Sent: Thu 06/09/2007 10:02
To: wra...@li...
Subject: Re: [Wrapper-user] Log4j with the wrapper
=20
Please find wrapper.conf and log4j.properties file attached.
=20
This is how i am initializing in my java program.
static Logger logger =3D Logger.getRootLogger();
=20
----- Original Message -----
From: wra...@li... on behalf of Rodrigo =
Vega=20
Sent: Thu, 6/9/2007 13:44
To: wra...@li...
Subject: Re: [Wrapper-user] Log4j with the wrapper=20
=20
=20
I have a very similar problem a couple of weeks ago... An the wrapper =
works
fine.=20
Attach your wrapper.conf and show me how you are initializing your =
log4j. If
you are loading your log4j.xml from the classpath there are many =
possible
problems like:
log4j doesn't found the log4j.xml in the classpath
you have multiples log4j.xml in your classpath and is not loading the =
right
one
etc..
Regards..
Rodrigo G. Vega
i411 Argentina
rv...@i4...
Este mensaje es confidencial. Si usted ha recibido este e-mail por =
error, por
favor comun=EDquenoslo inmediatamente v=EDa e-mail y tenga la amabilidad =
de
eliminarlo de su sistema; no deber=E1 copiar el mensaje ni divulgar su
contenido a ninguna persona. Muchas gracias.
This message is confidential. If you have received it by mistake please =
let
us know by e-mail immediately and delete it from your system; you should =
also
not copy the message nor disclose its contents to anyone. Many thanks.
-----Original Message-----
From: wra...@li... on behalf of Sujatha
Bharathan
Sent: Thu 06/09/2007 6:01
To: wra...@li...
Subject: [Wrapper-user] Log4j with the wrapper
Hi,
I am using the webservice to create a windows service for my java =
program. I
have configured log4j for seeing hte logging for my java file.
But i see that my log file is not created at all. I see a wrapper.log =
file
and all my console output appears in the wrapper.log. But i am expecting =
all
the same in my logfile.
Does the wrapper override any existing configuration for log4j and can =
write
only inside the configuration file of the wrapper?
Is there any work around for this?
Thanks
Sujie
|
|
From: Sujatha B. <suj...@td...> - 2007-09-06 13:02:36
|
Please find wrapper.conf and log4j.properties file attached.
=20
This is how i am initializing in my java program.
static Logger logger =3D Logger.getRootLogger();
=20
----- Original Message -----
From: wra...@li... on behalf of Rodrigo Vega=
=20
Sent: Thu, 6/9/2007 13:44
To: wra...@li...
Subject: Re: [Wrapper-user] Log4j with the wrapper=20
=20
=20
I have a very similar problem a couple of weeks ago... An the wrapper works
fine.=20
Attach your wrapper.conf and show me how you are initializing your log4j. I=
f
you are loading your log4j.xml from the classpath there are many possible
problems like:
log4j doesn't found the log4j.xml in the classpath
you have multiples log4j.xml in your classpath and is not loading the right
one
etc..
Regards..
Rodrigo G. Vega
i411 Argentina
rv...@i4...
Este mensaje es confidencial. Si usted ha recibido este e-mail por error, p=
or
favor comun=EDquenoslo inmediatamente v=EDa e-mail y tenga la amabilidad de
eliminarlo de su sistema; no deber=E1 copiar el mensaje ni divulgar su
contenido a ninguna persona. Muchas gracias.
This message is confidential. If you have received it by mistake please let
us know by e-mail immediately and delete it from your system; you should al=
so
not copy the message nor disclose its contents to anyone. Many thanks.
-----Original Message-----
From: wra...@li... on behalf of Sujatha
Bharathan
Sent: Thu 06/09/2007 6:01
To: wra...@li...
Subject: [Wrapper-user] Log4j with the wrapper
Hi,
I am using the webservice to create a windows service for my java program. =
I
have configured log4j for seeing hte logging for my java file.
But i see that my log file is not created at all. I see a wrapper.log file
and all my console output appears in the wrapper.log. But i am expecting al=
l
the same in my logfile.
Does the wrapper override any existing configuration for log4j and can writ=
e
only inside the configuration file of the wrapper?
Is there any work around for this?
Thanks
Sujie |
|
From: Sujatha B. <suj...@td...> - 2007-09-06 12:58:36
|
I did try to set the log level to debug.=20
When you start a java thread using wrapper, it does not really return anyth=
ing. It starts running in the background.
=20
So how do i specify in the config file about this. It says it re-tries for =
5 times and complains cannot be started.
Please find attached a copy of wrapper.conf file .=20
=20
----- Original Message -----
From: wra...@li... on behalf of Rodrigo Vega=
=20
Sent: Thu, 6/9/2007 13:39
To: wra...@li...
Subject: Re: [Wrapper-user] Help regarding starting a service=20
=20
=20
Did you try to set your log level to debug and see the command line that
wrapper is trying to execute?
Maybe the problem is in another place...
If you attach your wrapper.conf and some lines of log maybe i can help you
more.
Regards
Rodrigo G. Vega
i411 Argentina
rv...@i4...
Este mensaje es confidencial. Si usted ha recibido este e-mail por error, p=
or
favor comun=EDquenoslo inmediatamente v=EDa e-mail y tenga la amabilidad de
eliminarlo de su sistema; no deber=E1 copiar el mensaje ni divulgar su
contenido a ninguna persona. Muchas gracias.
This message is confidential. If you have received it by mistake please let
us know by e-mail immediately and delete it from your system; you should al=
so
not copy the message nor disclose its contents to anyone. Many thanks.
-----Original Message-----
From: wra...@li... on behalf of Sujatha
Bharathan
Sent: Thu 06/09/2007 5:33
To: wra...@li...
Subject: Re: [Wrapper-user] Help regarding starting a service
Hi,
I tried that..but still the java is not returning and the wrapper is givin =
a
message saying=20
that unable to start the service after trying 5 times.
How do i handle this? Is this something to be fixed with wrapper or with th=
e
java?
My program will be running as a background thread..and is not suppose to
return until you execute stop on the service.
Please guide me
Thanks
Sujie=20
----- Original Message -----
From: wra...@li... on behalf of Rodrigo Vega=
=20
Sent: Wed, 5/9/2007 18:17
To: wra...@li...
Subject: Re: [Wrapper-user] Help regarding starting a service=20
I think your are making a main method, and this method call a thread. If th=
is
is your case you must do something like
public static void main(String args[]){
YourThread t =3D new YoruThread();
t.start();
t.join();
}
In that way your java program will not day until the thread die.
Rodrigo G. Vega
i411 Argentina
rv...@i4...
Este mensaje es confidencial. Si usted ha recibido este e-mail por error, p=
or
favor comun=EDquenoslo inmediatamente v=EDa e-mail y tenga la amabilidad de
eliminarlo de su sistema; no deber=E1 copiar el mensaje ni divulgar su
contenido a ninguna persona. Muchas gracias.
This message is confidential. If you have received it by mistake please let
us know by e-mail immediately and delete it from your system; you should al=
so
not copy the message nor disclose its contents to anyone. Many thanks.
-----Original Message-----
From: wra...@li... on behalf of Sujatha
Bharathan
Sent: Wed 05/09/2007 12:28
To: wra...@li...
Subject: [Wrapper-user] Help regarding starting a service
Hi,
I have used the wrapper class to create a windows service . I am successful
in creating the service but have an issue in starting it.
My service calls a java and the java starts a thread to run and it does not
return anything and has to keep running in the background.
But when i click on start in administrative tools>> service>> my service i=
t
comes back and says unable to start and it failed.
My java program is a thread and it will not return anything , Is there any
configuration variable which i could specify in my conf file so that i coul=
d
just run the java program
and return immediately without waiting for an output?
Looking forward for your help.
Thanks in advance.
Sujie
-------------------------------------------------------------------------
This SF.net email is sponsored by: Splunk Inc.
Still grepping through log files to find problems? Stop.
Now Search log events and configuration files using AJAX and a browser.
Download your FREE copy of Splunk now >> http://get.splunk.com/
_______________________________________________
Wrapper-user mailing list
Wra...@li...
https://lists.sourceforge.net/lists/listinfo/wrapper-user |
|
From: Hubert F. <hub...@ab...> - 2007-09-06 12:44:26
|
maybe it is your start method, that does not return....
Your start method must return and return NULL to indicate a successful =
startup. If not, wrapper assumes, you application hung on startup, kills =
it and restarts it.
Hubert
>>> "Rodrigo Vega" <rv...@i4...> 06.09.2007 14:36 >>>
Did you try to set your log level to debug and see the command line that
wrapper is trying to execute?
Maybe the problem is in another place...
If you attach your wrapper.conf and some lines of log maybe i can help you
more.
Regards
Rodrigo G. Vega
i411 Argentina
rv...@i4...=20
=20
Este mensaje es confidencial. Si usted ha recibido este e-mail por error, =
por
favor comun=C3=ADquenoslo inmediatamente v=C3=ADa e-mail y tenga la =
amabilidad de
eliminarlo de su sistema; no deber=C3=A1 copiar el mensaje ni divulgar su
contenido a ninguna persona. Muchas gracias.
=20
This message is confidential. If you have received it by mistake please =
let
us know by e-mail immediately and delete it from your system; you should =
also
not copy the message nor disclose its contents to anyone. Many thanks.
-----Original Message-----
From: wra...@li... on behalf of Sujatha
Bharathan
Sent: Thu 06/09/2007 5:33
To: wra...@li...=20
Subject: Re: [Wrapper-user] Help regarding starting a service
=20
Hi,
=20
I tried that..but still the java is not returning and the wrapper is givin =
a
message saying=20
that unable to start the service after trying 5 times.
=20
How do i handle this? Is this something to be fixed with wrapper or with =
the
java?
My program will be running as a background thread..and is not suppose to
return until you execute stop on the service.
=20
Please guide me
=20
Thanks
Sujie=20
=20
----- Original Message -----
From: wra...@li... on behalf of Rodrigo =
Vega=20
Sent: Wed, 5/9/2007 18:17
To: wra...@li...=20
Subject: Re: [Wrapper-user] Help regarding starting a service=20
=20
=20
I think your are making a main method, and this method call a thread. If =
this
is your case you must do something like
public static void main(String args[]){
YourThread t =3D new YoruThread();
t.start();
t.join();
}
In that way your java program will not day until the thread die.
Rodrigo G. Vega
i411 Argentina
rv...@i4...=20
Este mensaje es confidencial. Si usted ha recibido este e-mail por error, =
por
favor comun=C3=ADquenoslo inmediatamente v=C3=ADa e-mail y tenga la =
amabilidad de
eliminarlo de su sistema; no deber=C3=A1 copiar el mensaje ni divulgar su
contenido a ninguna persona. Muchas gracias.
This message is confidential. If you have received it by mistake please =
let
us know by e-mail immediately and delete it from your system; you should =
also
not copy the message nor disclose its contents to anyone. Many thanks.
-----Original Message-----
From: wra...@li... on behalf of Sujatha
Bharathan
Sent: Wed 05/09/2007 12:28
To: wra...@li...=20
Subject: [Wrapper-user] Help regarding starting a service
Hi,
I have used the wrapper class to create a windows service . I am successful=
in creating the service but have an issue in starting it.
My service calls a java and the java starts a thread to run and it does =
not
return anything and has to keep running in the background.
But when i click on start in administrative tools>> service>> my service =
it
comes back and says unable to start and it failed.
My java program is a thread and it will not return anything , Is there any
configuration variable which i could specify in my conf file so that i =
could
just run the java program
and return immediately without waiting for an output?
Looking forward for your help.
Thanks in advance.
Sujie
-------------------------------------------------------------------------
This SF.net email is sponsored by: Splunk Inc.
Still grepping through log files to find problems? Stop.
Now Search log events and configuration files using AJAX and a browser.
Download your FREE copy of Splunk now >> http://get.splunk.com/=20
_______________________________________________
Wrapper-user mailing list
Wra...@li...=20
https://lists.sourceforge.net/lists/listinfo/wrapper-user=20
|
|
From: Rodrigo V. <rv...@i4...> - 2007-09-06 12:43:03
|
I have a very similar problem a couple of weeks ago... An the wrapper = works fine.=20 Attach your wrapper.conf and show me how you are initializing your = log4j. If you are loading your log4j.xml from the classpath there are many = possible problems like: log4j doesn't found the log4j.xml in the classpath you have multiples log4j.xml in your classpath and is not loading the = right one etc.. Regards.. Rodrigo G. Vega i411 Argentina rv...@i4... =20 Este mensaje es confidencial. Si usted ha recibido este e-mail por = error, por favor comun=EDquenoslo inmediatamente v=EDa e-mail y tenga la amabilidad = de eliminarlo de su sistema; no deber=E1 copiar el mensaje ni divulgar su contenido a ninguna persona. Muchas gracias. =20 This message is confidential. If you have received it by mistake please = let us know by e-mail immediately and delete it from your system; you should = also not copy the message nor disclose its contents to anyone. Many thanks. -----Original Message----- From: wra...@li... on behalf of Sujatha Bharathan Sent: Thu 06/09/2007 6:01 To: wra...@li... Subject: [Wrapper-user] Log4j with the wrapper =20 Hi, =20 I am using the webservice to create a windows service for my java = program. I have configured log4j for seeing hte logging for my java file. =20 But i see that my log file is not created at all. I see a wrapper.log = file and all my console output appears in the wrapper.log. But i am expecting = all the same in my logfile. =20 Does the wrapper override any existing configuration for log4j and can = write only inside the configuration file of the wrapper? =20 Is there any work around for this? =20 Thanks Sujie |
|
From: Rodrigo V. <rv...@i4...> - 2007-09-06 12:39:00
|
Did you try to set your log level to debug and see the command line that
wrapper is trying to execute?
Maybe the problem is in another place...
If you attach your wrapper.conf and some lines of log maybe i can help =
you
more.
Regards
Rodrigo G. Vega
i411 Argentina
rv...@i4...
=20
Este mensaje es confidencial. Si usted ha recibido este e-mail por =
error, por
favor comun=EDquenoslo inmediatamente v=EDa e-mail y tenga la amabilidad =
de
eliminarlo de su sistema; no deber=E1 copiar el mensaje ni divulgar su
contenido a ninguna persona. Muchas gracias.
=20
This message is confidential. If you have received it by mistake please =
let
us know by e-mail immediately and delete it from your system; you should =
also
not copy the message nor disclose its contents to anyone. Many thanks.
-----Original Message-----
From: wra...@li... on behalf of Sujatha
Bharathan
Sent: Thu 06/09/2007 5:33
To: wra...@li...
Subject: Re: [Wrapper-user] Help regarding starting a service
=20
Hi,
=20
I tried that..but still the java is not returning and the wrapper is =
givin a
message saying=20
that unable to start the service after trying 5 times.
=20
How do i handle this? Is this something to be fixed with wrapper or with =
the
java?
My program will be running as a background thread..and is not suppose to
return until you execute stop on the service.
=20
Please guide me
=20
Thanks
Sujie=20
=20
----- Original Message -----
From: wra...@li... on behalf of Rodrigo =
Vega=20
Sent: Wed, 5/9/2007 18:17
To: wra...@li...
Subject: Re: [Wrapper-user] Help regarding starting a service=20
=20
=20
I think your are making a main method, and this method call a thread. If =
this
is your case you must do something like
public static void main(String args[]){
YourThread t =3D new YoruThread();
t.start();
t.join();
}
In that way your java program will not day until the thread die.
Rodrigo G. Vega
i411 Argentina
rv...@i4...
Este mensaje es confidencial. Si usted ha recibido este e-mail por =
error, por
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-----Original Message-----
From: wra...@li... on behalf of Sujatha
Bharathan
Sent: Wed 05/09/2007 12:28
To: wra...@li...
Subject: [Wrapper-user] Help regarding starting a service
Hi,
I have used the wrapper class to create a windows service . I am =
successful
in creating the service but have an issue in starting it.
My service calls a java and the java starts a thread to run and it does =
not
return anything and has to keep running in the background.
But when i click on start in administrative tools>> service>> my service =
it
comes back and says unable to start and it failed.
My java program is a thread and it will not return anything , Is there =
any
configuration variable which i could specify in my conf file so that i =
could
just run the java program
and return immediately without waiting for an output?
Looking forward for your help.
Thanks in advance.
Sujie
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|
|
From: Sujatha B. <suj...@td...> - 2007-09-06 09:01:47
|
Hi, I am using the webservice to create a windows service for my java program. I have configured log4j for seeing hte logging for my java file. But i see that my log file is not created at all. I see a wrapper.log file and all my console output appears in the wrapper.log. But i am expecting all the same in my logfile. Does the wrapper override any existing configuration for log4j and can write only inside the configuration file of the wrapper? Is there any work around for this? Thanks Sujie |
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