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From: Alex V. <ale...@ap...> - 2004-02-17 00:26:18
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Hi, I'm configuring the wrapper to never timeout = (wrapper.startup.timeout=3D0), but I still get a popup error message from windows after about 2 mins: "Could not start the 'myService' service on local computer. Error 1053: = the service did not respond to the start or control request in a timely = fashion" I've also tried with 300 (5mns) and did not see any difference. Any idea ? Thanks, Alex. |