Re: [Wrapl-discussion] expr1 \ expr2

[Raja M. <raj...@gm...>]

Hi Roman,

Thanks for pointing out the error in the tutorial. The implementation is 
correct though, ALL 1:to(3) \ 10:to(12); should return [1, 1, 1, 2, 2, 
2, 3, 3, 3], the values of (left for each right). This follows the 
general rule of left-to-right evaluation in Wrapl.

In general A & B is equivalent to 2(A, B) and A \ B is equivalent to 
1(A, B). The description in the tutorial is ambiguous though, I'll 
update the description along with the other changes you mentioned 
previously.

Raja

Roman Mishin wrote:
> Hi Raja,
>
> I noticed one small inconsistency with "expr1 \ expr2"
>
> Tutorial Chapter 3 
> (http://wrapl.sourceforge.net/ref/tutorial/chapter3.html)
>
> "expr1 \ expr2 produces the values produced by expr1 for each value 
> produced by expr2"
>
> ALL 1:to(3) \ 10:to(12);
> actualy returns
> [1, 1, 1, 2, 2, 2, 3, 3, 3]
> not
> [1, 2, 3, 1, 2, 3, 1, 2, 3]
> as the example shows
>
> Tutorial states that "expr1 \ expr2" is similar to "expr1 & expr2", 
> such that it returns the value of left for each right, in contrast to 
> the value of right for each left. But that (factual) way their (& and 
> \) results are not symmetrical.
>
> --
> the values of (left for each right) [1, 1, 1, 2, 2, 2, 3, 3, 3]
> vs.
> (the values of left) for each right [1, 2, 3, 1, 2, 3, 1, 2, 3]
> --
>
> I guess it would make sense for it to behave that way: [1, 2, 3, 1, 2, 
> 3, 1, 2, 3]
>
> --
> Roman
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