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Webware for Python

The Classic Webware for Python

Brought to you by: cito, echuck, gtalvola, stuartd

Re: [Webware-discuss] webware on Linux VServer

Re: [Webware-discuss] webware on Linux VServer

From: Christoph Zwerschke <cito@on...> - 2006-11-15 20:57:33

Randall Smith wrote:
> I'm trying to get webware going on VServer, but I'm getting the error below.
 > ...
> "/usr/local/lib/python2.4/site-packages/webware/WebKit/NewThreadedAppServer.py", 
> ...

That looks like a very old Webware. Did you try with Webware 0.9.2?

-- Chris

Thread view

[Webware-discuss] webware on Linux VServer

From: Randall Smith <randall@tn...> - 2006-11-14 22:40:27

I'm trying to get webware going on VServer, but I'm getting the error below.

Listening on ('127.0.0.1', 8086)
Ready  (0.36 seconds after launch)

Listening on ('127.0.0.1', 8080)
('192.168.1.203', 8080)
Traceback (most recent call last):
   File 
"/usr/local/lib/python2.4/site-packages/webware/WebKit/NewThreadedAppServer.py", 
line 530, in run
     server.mainloop()
   File 
"/usr/local/lib/python2.4/site-packages/webware/WebKit/NewThreadedAppServer.py", 
line 140, in mainloop
     handler = self._handlerCache[serverAddress].pop()
KeyError: ('192.168.1.203', 8080)

I'm accessing it from 192.168.1.102.  I'm sure it's a VServer routing 
thing, but I haven't had trouble with Apache, Postgres, SSH, etc. 
Looking at the code, socket.getsockname() is returning 192.168.1.203. 
If I put this in:

     except KeyError:
         handler = self._handlerCache[(127.0.0.1, serverAddress[1])].pop()

It then says that I'm trying to pop from an empty list.  Ideas?

Randall

Re: [Webware-discuss] webware on Linux VServer

From: Randall Smith <randall@tn...> - 2006-11-14 22:45:35

Randall Smith wrote:
> I'm trying to get webware going on VServer, but I'm getting the error below.
> 
> Listening on ('127.0.0.1', 8086)
> Ready  (0.36 seconds after launch)
> 
> Listening on ('127.0.0.1', 8080)
> ('192.168.1.203', 8080)
> Traceback (most recent call last):
>    File 
> "/usr/local/lib/python2.4/site-packages/webware/WebKit/NewThreadedAppServer.py", 
> line 530, in run
>      server.mainloop()
>    File 
> "/usr/local/lib/python2.4/site-packages/webware/WebKit/NewThreadedAppServer.py", 
> line 140, in mainloop
>      handler = self._handlerCache[serverAddress].pop()
> KeyError: ('192.168.1.203', 8080)
> 
> I'm accessing it from 192.168.1.102.  I'm sure it's a VServer routing 
> thing, but I haven't had trouble with Apache, Postgres, SSH, etc. 
> Looking at the code, socket.getsockname() is returning 192.168.1.203. 
> If I put this in:
> 
>      except KeyError:
>          handler = self._handlerCache[(127.0.0.1, serverAddress[1])].pop()
> 
> It then says that I'm trying to pop from an empty list.  Ideas?
> 
> Randall
> 	

self._handlerCache looks like this:

{('127.0.0.1', 8080): [], ('127.0.0.1', 8086): []}


Randall

Re: [Webware-discuss] webware on Linux VServer

From: Randall Smith <randall@tn...> - 2006-11-14 22:56:46

Randall Smith wrote:
> I'm trying to get webware going on VServer, but I'm getting the error below.
> 
> Listening on ('127.0.0.1', 8086)
> Ready  (0.36 seconds after launch)
> 
> Listening on ('127.0.0.1', 8080)
> ('192.168.1.203', 8080)
> Traceback (most recent call last):
>    File 
> "/usr/local/lib/python2.4/site-packages/webware/WebKit/NewThreadedAppServer.py", 
> line 530, in run
>      server.mainloop()
>    File 
> "/usr/local/lib/python2.4/site-packages/webware/WebKit/NewThreadedAppServer.py", 
> line 140, in mainloop
>      handler = self._handlerCache[serverAddress].pop()
> KeyError: ('192.168.1.203', 8080)
> 
> I'm accessing it from 192.168.1.102.  I'm sure it's a VServer routing 
> thing, but I haven't had trouble with Apache, Postgres, SSH, etc. 
> Looking at the code, socket.getsockname() is returning 192.168.1.203. 
> If I put this in:
> 
>      except KeyError:
>          handler = self._handlerCache[(127.0.0.1, serverAddress[1])].pop()
> 
> It then says that I'm trying to pop from an empty list.  Ideas?
> 
> Randall
> 	

NewThreadedAppServer.py:140

This works, but obviously isn't proper:

     if serverAddress not in self._handlerCache:
         serverAddress = ('127.0.0.1', serverAddress[1])

Randall

Re: [Webware-discuss] webware on Linux VServer

From: Christoph Zwerschke <cito@on...> - 2006-11-15 20:57:33

Randall Smith wrote:
> I'm trying to get webware going on VServer, but I'm getting the error below.
 > ...
> "/usr/local/lib/python2.4/site-packages/webware/WebKit/NewThreadedAppServer.py", 
> ...

That looks like a very old Webware. Did you try with Webware 0.9.2?

-- Chris

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