Re: [Vtd-xml-users] reading zipped xml files

[Jimmy Z. <cra...@co...>]

It seems that the XML file you gunzipped contains well-formedness error
can you visually check it (go to line 22)

Jimmy
  ----- Original Message -----=20
  From: G. P.=20
  To: vtd...@li...=20
  Sent: Monday, May 14, 2007 4:08 AM
  Subject: [Vtd-xml-users] reading zipped xml files


  Hi List,

  I am trying to read from a gzipped xml file, with the following code :

  GZIPInputStream gz =3D new GZIPInputStream(new FileInputStream =
(file));

  byte[] b =3D new byte[(int) 2*1024]; //max file size
  gz.read(b);
         =20
   VTDGen vg =3D new VTDGen();
  vg.setDoc(b);
  vg.parse(false);


  But I get an=20
  Exception in thread "main" com.ximpleware.ParseException: Starting tag =
Error: Invalid char in starting tag
  Line Number: 22 Offset: 15
      at com.ximpleware.VTDGen.parse(VTDGen.java:1388)



  Can someone point me how I can read directly from a gz file ?

  thanks in advance
  gpio



-------------------------------------------------------------------------=
-----
  =D7=F1=E7=F3=E9=EC=EF=F0=EF=E9=E5=DF=F4=E5 Yahoo!
  =C2=E1=F1=E5=E8=DE=EA=E1=F4=E5 =F4=E1 =E5=ED=EF=F7=EB=E7=F4=E9=EA=DC =
=EC=E7=ED=FD =EC=E1=F4=E1 (spam); =D4=EF Yahoo! Mail =
=E4=E9=E1=E8=DD=F4=E5=E9 =F4=E7=ED =EA=E1=EB=FD=F4=E5=F1=E7 =
=E4=F5=ED=E1=F4=DE =F0=F1=EF=F3=F4=E1=F3=DF=E1 =EA=E1=F4=DC =F4=F9=ED =
=E5=ED=EF=F7=EB=E7=F4=E9=EA=FE=ED =EC=E7=ED=F5=EC=DC=F4=F9=ED=20
  http://login.yahoo.com/config/mail?.intl=3Dgr=20


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