Re: [Valgrind-users] "still reachable" memory from g++'sstd::string

[Olly B. <ol...@su...>]

On Wed, Apr 02, 2003 at 11:23:34AM -0500, Maarten Ballintijn wrote:
> >         >           {
> >         >             std::string s;
> >         >             s += '0';
> >         >           }
> >         >           exit(0);

> Just out of curiosity, why would s be destructed if you call exit()?

s is destructed at the end of the block where it's defined - i.e. the
line before exit is called.

Cheers,
    Olly