Re: [Valgrind-users] Address 0xNNNNN is N bytes inside a block of size N alloc'd

[Pavel S. <pac...@gm...>]

> So the address 0xNNNNN is the Y'th byte after the start of the block you got.
> The range of the block is:
>
> [0xNNNNN - Y, 0xNNNNN - Y + X)

Thanks for clarification

-- 
Best regards, Pavel