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From: Felipe A. <fel...@gm...> - 2008-06-13 03:30:21
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Oh well, here I am again, again with the math issue: ==6464== L2 refs: 1,674 ( 1,510 rd + 164 wr) ==6464== L2 misses: 1,586 ( 1,430 rd + 156 wr) ==6464== L2 miss rate: 0.9% ( 0.9% + 0.9% ) l2 refs 1674 l2 misses 1586, how come it says 0,9% miss rate? 2008/6/12 Felipe Athayde <fel...@gm...>: > Oops, math mistake :P > > I just finished my work. Thank you to both of you who helped me. > > Regards~ > > 2008/6/12 Hien Le <Hi...@me...>: > > There were 115773 instruction refs total, of which 611 references were I1 >> misses. 661 / 115773 = 0.52%. >> >> >> Thanks once again! >>> >>> Now, in the end of the test, I have to analize all the data collected and >>> I >>> found another barrier for succeeding in such task. >>> >>> I couldn't figure out how the miss rates work, because if there were >>> 115773 >>> references on I, no way 611 is 0.52%, it should be 1.89%, same goes for >>> all >>> the others miss rates. Am I missing something? >>> ==6464== I refs: 115,773 >>> ==6464== I1 misses: 611 >>> ==6464== L2i misses: 609 >>> ==6464== I1 miss rate: 0.52% *-> this should be 1,89%, isn't >>> it? x=115773/(611*100)* >>> ==6464== L2i miss rate: 0.52% >>> ==6464== >>> ==6464== D refs: 57,878 (41,851 rd + 16,027 wr) >>> ==6464== D1 misses: 1,063 ( 899 rd + 164 wr) >>> ==6464== L2d misses: 977 ( 821 rd + 156 wr) >>> ==6464== D1 miss rate: 1.8% ( 2.1% + 1.0% ) >>> ==6464== L2d miss rate: 1.6% ( 1.9% + 0.9% ) >>> ==6464== >>> ==6464== L2 refs: 1,674 ( 1,510 rd + 164 wr) >>> ==6464== L2 misses: 1,586 ( 1,430 rd + 156 wr) >>> ==6464== L2 miss rate: 0.9% ( 0.9% + 0.9% ) >>> >>> Kind regards >>> >> > > > -- > Felipe > > > > -- > Felipe -- Felipe |