Re: [tipc-discussion] TIPC socket ( SOCK_SEQPACKET) cleanup issue

[Tung Q. N. <tun...@de...>]

From: prakash bisht <ps1...@gm...>
Sent: Monday, April 17, 2023 11:20 AM
To: tip...@li...; Xin Long <lx...@re...>; Tung Quang Nguyen <tun...@de...>; jm...@re...
Subject: Fwd: TIPC socket ( SOCK_SEQPACKET) cleanup issue

Hi John/Xin,Tung,

Any thoughts on my previous email? We are using tipc for our product for quite a while and started facing this issue recently in a specific scenario we launch strace to monitor another process.
Also is there any way to deny creation of another tipc socket with the same tipc address ?  In our case applications need a unique tipc server socket.
>>> There is no limitation for creating many sockets binding to the same tipc address. Why you need “a unique tipc server socket” ? Can you provide your code to demonstrate your use case ?

Thanks and Regards,
Prakash
---------- Forwarded message ---------
From: prakash bisht <ps1...@gm...<mailto:ps1...@gm...>>
Date: Mon, Apr 3, 2023 at 4:33 PM
Subject: TIPC socket ( SOCK_SEQPACKET) cleanup issue
To: <tip...@li...<mailto:tip...@li...>>

Hi all,

I am facing an issue while closing the TIPC server socket. In certain scenarios, even after closing the server socket fd the ‘tipc socket list’ is still showing it as alive.
>>> What is you iproute2 version ? Can you provide your code to demonstrate your use case ?
I am sure that the fd has been closed as the next socket creation request gets the same fd from linux. Even when the process exits, the stale socket entry is still present in the ‘tipc socket list’ and it vanishes only after rebooting the system.
 Kernel version : 4.19.81
Socket type :      SOCK_SEQPACKET

Also, is there any way of finding out whether a tipc socket belongs to which linux process ?
>>> There is no command to know which tipc socket belongs to which Linux process. But you can use function getsockname() to print out the port id after creating a socket. Then you know the created socket belongs to the calling process.

Would appreciate any help.

Thanks,
Prakash