If you have the zip file in RAM you can construct a ByteArrayInputStream();

something like this:

      byte a[]= "foo".getBytes();
      ByteArrayInputStream i = new ByteArrayInputStream(a);
      return new StreamingResolution("application/zip", i);

If the file is static and stored within the web app, you may just be able to make a ForwardResolution() assuming the mime type is mapped.

The documentation provides a nice example showing to really stream the content using an inner class:


return new StreamingResolution("text/xml") {
    public void stream(HttpServletResponse response) throws Exception {

In this case, you can write the bytes of the zip file using:

On Aug 24, 2009, at 2:11 PM, Laurent Perez wrote:


I need to serve a zip file directly from a returning Resolution
(redirecting to the generated zip file is not an option).
The zip file is not big, a few KB.

I've played with the StreamingResolution, but I still can't manage to
get it right : the content type is of course "application/zip", but
what's the best option for the second argument : should I be using an
InputStream or a Reader ?

Thanks for any input


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