[SQLObject] Re: unknown column table creation..novice
SQLObject is a Python ORM.
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From: Brian R. <br...@se...> - 2004-08-19 14:37:00
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>> I am looking for a way to created a table from a list of values. Say I have:
>>
>> headers = ['bbd_id', 'co_name1', 'address1', 'address2', 'city',
>> 'state', 'zip5', 'zip4', 'first_name', 'surname', 'telephone']
>
> class MailList(SQLObject):
> pass
>
> for header in headers:
> MailList.addColumn(Col(name=header))
This works great, thnx!
Next I want to create a new record:
rows = zip(headers,cell)
line_item = MailList.new(*rows)
However the new method does not like this argument list:
TypeError: new() takes exactly 1 argument (16 given)
When I explicitly write out all 16 arguments, it works.
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