Re: [SQLObject] list index out of range?

[Luke O. <lu...@me...>]

Mike -

listofpersons (and any return of select()) is a list, not a dictionary keyed by
ids. So listofpersons[newid] is almost guaranteed to be out of range (if your
database ids start at 1 and list indexes start at 0, then even with no deleted
Persons it will be wrong), and even if not out of range probably not the
object you wanted.

If you want a specific Person, use Person(newid), if you want a list of Persons
from select() treat them as a list (ie, iterate through them as you mentioned
works, or access by positional index, etc).

- Luke

Quoting Mike Edmonds <mi...@mi...>:

> Can anyone tell me why I get the following error? I am creating a new
> object, and then trying to access that object via a newly queried second
> object. And getting a list index out of range error. If I simply iterate
> through the new list (without referring to the item by index) then it will
> appear in the list. If I run a different script with the same code querying
> the table I can access it okay.
>
>
> from SQLObject import *
>
>
> class Person(SQLObject):
>     _connection = MySQLConnection(host='localhost', db='jcpos',
>                            user='test', passwd='')
>     first_name = StringCol(length=100,default="")
>     middle_initial = StringCol(length=1, default="")
>     last_name = StringCol(length=100, default="")
>
>
> newperson = Person.new(first_name="Mike")
> newid = newperson.id
>
> listofpersons = Person.select()
> print listofpersons[newid].first_name
>
> Traceback (most recent call last):
>   File "D:\dev\pythontest\sqlerror.py", line 18, in ?
>     print listofpersons[newid].first_name
>   File "C:\Python23\Lib\site-packages\SQLObject\SQLObject.py", line 1056, in
> __g
> etitem__
>     return list(self.clone(start=value, stop=value+1))[0]
> IndexError: list index out of range