Re: [SQLObject] Re: SQLObject

[Bud P. B. <bu...@si...>]

On 11 Apr 2003 01:37:10 -0500
Ian Bicking <ia...@co...> wrote:

> > Site
> > site_id PK
> > ...
> > 
> > User
> > user_id PK
> > ...
> > 
> > UserSite
> > user_id	FK
> > site_id FK 
> > (together they're the PK)
> > ...
> 
> This seems like a many-to-many relation, which SQLObject doesn't
> represent as a Python object, and which doesn't require any ID.  

The difference to many-to-many relationships (in my understanding) is
that the "breakup" table has many more columns than just necessary for
linking.  

--b

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