[SQL-CVS] r492 - home/phd/SQLObject/inheritance/docs

[<sub...@co...>]

Author: phd
Date: 2004-12-16 14:23:48 +0000 (Thu, 16 Dec 2004)
New Revision: 492

Modified:
   home/phd/SQLObject/inheritance/docs/Inheritance.txt
Log:
Minor fix for SQLObject 0.6 API.

Modified: home/phd/SQLObject/inheritance/docs/Inheritance.txt
===================================================================
--- home/phd/SQLObject/inheritance/docs/Inheritance.txt	2004-12-16 14:23:02 UTC (rev 491)
+++ home/phd/SQLObject/inheritance/docs/Inheritance.txt	2004-12-16 14:23:48 UTC (rev 492)
@@ -55,7 +55,7 @@
 
     p = Person(firstName='John', lastName='Doe')
     e = Employee(firstName='Jane', lastName='Doe', position='Chief')
-    p2 = Person(1)
+    p2 = Person.get(1)
 
 Will create the following data in the database::
 
@@ -97,8 +97,8 @@
 
 The SQLObject q magic also work.  Using this select are valid::
 
-    Employee.select(Employee.q.firstName == 'Jane' & Employee.q.position == 'Chief') will return Jane Doe
-    Employee.select(Person.q.firstName == 'Jane' & Employee.q.position == 'Chief') will return Jane Doe
+    Employee.select(AND(Employee.q.firstName == 'Jane' Employee.q.position == 'Chief')) will return Jane Doe
+    Employee.select(AND(Person.q.firstName == 'Jane', Employee.q.position == 'Chief')) will return Jane Doe
     Employee.select(Employee.q.lastName == 'Doe') will only return Jane Doe (as Joe isn't an employee)
     Person.select(Person.q.lastName == 'Doe') will return both entries.