From: Oleg B. <ph...@ph...> - 2012-06-21 20:56:08
|
On Thu, Jun 21, 2012 at 10:45:40PM +0200, Petr Jake?? <pet...@tp...> wrote: > I am sure Oleg is reading this and > gives his comments about the issue. I think there have to be a way to generate id's for a complex VIEW by, e.g., combining id's into a string with a delimiter; SQLObject supports string id. Or calculating a hash value of that combined id and using the hash as the id. Oleg. -- Oleg Broytman http://phdru.name/ ph...@ph... Programmers don't die, they just GOSUB without RETURN. |