Re: [Sndobj-devel] DelayLine question

[Victor L. <Vic...@nu...>]

Use a Mixer object and mix the two signals:

Mixer mix
mix.AddObj(delay)
mix.AddObj(osc)
outp.SetOutput(mix)

(Or use a SndRTThread object that has a builtin mixer for each output
channel.)

Victor

At 19:28 11/07/2007, you wrote:
>Hi all!
>
>I'm new to SndObj. Hope someone can help me with this. I was trying a 
>DelayLine object but with no luck. Here is what I've got:
>import sndobj
>import time
>
>tab = sndobj.HarmTable()
>env = sndobj.Interp(5000, 0, 0.1, 2)
>osc = sndobj.Oscili(tab, 440, 0, None, env)
>delay = sndobj.DelayLine(0.5, osc)
>outp = sndobj.SndRTIO(1)
>outp.SetOutput(1, osc)
>outp.SetOutput(1, delay)
>thread = sndobj.SndThread ()
>thread.AddObj(osc)
>thread.AddObj(env)
>thread.AddObj(delay)
>thread.AddObj(outp, sndobj.SNDIO_OUT)
>thread.ProcOn()
>time.sleep(2)
>thread.ProcOff()
>
>Now, I can hear only delayed signal. But how can hear the original also? 
>It should be possible(?).
>Thanks.
>
>Bosko
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Victor Lazzarini
Music Technology Laboratory
Music Department
National University of Ireland, Maynooth