Re: [Simple-support] Deserialize any element (xsd:any)

[Niall G. <gal...@ya...>]

Hi,

Check out the tutorial, it should have the details you need.

Niall
--------------------------------------------
On Sat, 8/11/14, Christian Schudt <chr...@gm...> wrote:

 Subject: [Simple-support] Deserialize any element (xsd:any)
 To: sim...@li...
 Received: Saturday, 8 November, 2014, 10:12 AM
 
 Hi all,
 
 I am trying to deserialize an XML String to an object.
 
 The problem I am having is that the object can have *any*
 element (xsd:any).
 
 I tried it that way:
 
 @Root
 public class Container
 {
     @Element(required = false)
     private Object anyElement;
 }
 
 But when deserializing the following XML:
 <container><xyz
 xmlns=„any_arbitrary_namespace“/></container>
 
 I get a org.simpleframework.xml.core.ElementException:
 Element ‚xyz' does not have a match in class…
 
 I have a class which would map to the xyz element.
 I also thought, that I have to register it (similar to
 creating a JAXBContext), so that the persister is aware of
 it, like:
 registry.lookup(Xyz.class);
 
 but I doesn’t work.
 
 Here’s the same question:
 http://stackoverflow.com/questions/26361729/simplexml-any-element-matching
 
 Thanks for help,
 Christian
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