Re: [Simple-support] Serializing inline list of "simple" elements

[Kevin J. <kjo...@in...>]

this works great - thanks!

-kevin

On May 28, 2008, at 12:01 AM, Timo Rumland wrote:

> Hi Kevin,
>
> the following code produces exactly the result you desire:
>
> ----------------------------
>
> public class SimpleXMLTest {
>
>  @Root
>  private class Event {
>
>    @Text
>    private String text;
>
>    public Event( String text ) {
>      this.text = text;
>    }
>
>    public String getText() {
>      return text;
>    }
>  }
>
>  @Root( name = "events" )
>  private class EventList {
>
>    @ElementList( inline = true )
>    private List< Event > events = new ArrayList< Event >();
>
>    public List< Event > getEvents() {
>      return events;
>    }
>  }
>
>  public SimpleXMLTest() throws Exception {
>
>    EventList list = new EventList();
>
>    list.getEvents().add( new Event( "foo" ) );
>    list.getEvents().add( new Event( "bar" ) );
>
>    Serializer serializer = new Persister();
>    serializer.write( list, System.out );
>  }
>
>  public static void main( String[] args ) throws Exception {
>    new SimpleXMLTest();
>  }
> }
> ----------------------------
>
>
> Please have a look at the "name" and "inline" annotation parameters -
> these control the "format" of the XML, so it looks like your XML
> example.
>
>
> Hope that helps
>
>
> Regards,
> Timo
>
>
>
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