Re: [Simple-support] Serializing inline list of "simple" elements

[Timo R. <cr...@ol...>]

Hi Kevin,

the following code produces exactly the result you desire:

----------------------------

public class SimpleXMLTest {

  @Root
  private class Event {

    @Text
    private String text;

    public Event( String text ) {
      this.text = text;
    }

    public String getText() {
      return text;
    }
  }
        
  @Root( name = "events" )
  private class EventList {

    @ElementList( inline = true )
    private List< Event > events = new ArrayList< Event >();

    public List< Event > getEvents() {
      return events;
    }
  }
        
  public SimpleXMLTest() throws Exception {
                
    EventList list = new EventList();
                
    list.getEvents().add( new Event( "foo" ) );
    list.getEvents().add( new Event( "bar" ) );
                
    Serializer serializer = new Persister();
    serializer.write( list, System.out );
  }
        
  public static void main( String[] args ) throws Exception {
    new SimpleXMLTest();
  }
}
----------------------------


Please have a look at the "name" and "inline" annotation parameters -
these control the "format" of the XML, so it looks like your XML
example.


Hope that helps


Regards,
Timo