I'm having trouble with with the -v command line option. I have a command:
7z a test.7z "c:\test"
This command works fine. It creates a test.7z file. There is around 150 MB of data in the c:\test folder. However, when I add a -v50m to the end of the command:
7z a test.7z "c:\test" -v50m
I get a 'System error: Not implemented' message. The intention is to have 3 files (presumably test.7z.001, test.7z.002, etc.) that are 50 MB each. Am I mis-understanding something?
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I figured it out, but it brings up another question. It didn't like the quotes around the folder name.
7z a test.7z c:\test -v50m
worked fine. So, if the folder had a space in it, how would I specify it on the command line?
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I'm having trouble with with the -v command line option. I have a command:
7z a test.7z "c:\test"
This command works fine. It creates a test.7z file. There is around 150 MB of data in the c:\test folder. However, when I add a -v50m to the end of the command:
7z a test.7z "c:\test" -v50m
I get a 'System error: Not implemented' message. The intention is to have 3 files (presumably test.7z.001, test.7z.002, etc.) that are 50 MB each. Am I mis-understanding something?
I figured it out, but it brings up another question. It didn't like the quotes around the folder name.
7z a test.7z c:\test -v50m
worked fine. So, if the folder had a space in it, how would I specify it on the command line?
remove the archive before the command
So:
7z a c:\test -v50m test.7z
That's different than what is in the help file.
quotes are required.
Or you can use list file, an no quotes inside list file.
But, with the quotes, it failed. Without the quotes it succeeded.
You must remove previous archive from NTFS volume before creating new archive.
Try this:
7z a -v50m test.7z "c:\test"