Xml output

[Felix C]

Hi,

I am using Saxon to transform a xml file into another using this xsl stylesheet:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0" xmlns:saxon="http://saxon.sf.net/">

<xsl:output method="xml" indent="yes" />
<xsl:strip-space elements="*"/>

<xsl:template match="/">
<foo>
.......
<xsl:text>&#xd;</xsl:text>
<bar>
..........
</bar>
<xsl:text>&#xd;</xsl:text>
<bar>
..........
</bar>
</foo>

</xsl:template>
</xsl:stylesheet>

So I am expecting to get something like that:

<foo>

<bar>........</bar>

<bar>........</bar>
</foo>

But the result is:

<foo>&#xd;
<bar>........</bar>&#xd;
<bar>........</bar>
</foo>

I am using the java virtual machine, with the following options:

java -cp saxon9he.jar net.sf.saxon.Transform -t -s:myInput.xml -xsl:mystylesheet.xsl -o:c:myoutput.xml

Thanks in advance for any help.

[Michael Kay]

Please use the Saxonica forum at saxonica.plan.io for saxon-specific questions, and SourceForge for general XSLT questions.

XML normalizes newlines to a single x0A character. If you just want a new line, output x0A. If you try to output x0D, it is output as a character reference in order to preserve it through end-of-line normalization when the XML file is re-parsed. This is mandated by the W3C specification.

[Felix C]

Thank you very much!!