select * from A full outer join B
generates a wrong graph (hedge is lost)
and this one:
select * from A full outer join (select * from T) B
doesn't generate any graph at all
Problem is with simplifier . Both theese work:
select * from A full outer join B on a.id=b.id
select * from A full outer join B on 0 and g(a.id) = f(b.id,0)
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