## Re: [Reduce-algebra-developers] Sum(1/x^2, x, 1, infinity);

 Re: [Reduce-algebra-developers] Sum(1/x^2, x, 1, infinity); From: Michael Borcherds - 2012-07-30 15:05:00 ```Thanks, using specfn is an improvement as sum(1/x^2,x,1,infinity); then works! However these still don't :) sum(1/(x+1)^2,x,1,infinity); sum(1/x^2,x,2,infinity); thanks, Mike On 30 July 2012 15:40, Arthur Norman wrote: > On Mon, 30 Jul 2012, Michael Borcherds wrote: > >> Hi, >> >> Is there any way to get Reduce to calculate this? >> Sum(1/x^2, x, 1, infinity); >> >> thanks! >> >> Mike >> > > You may not like this answer, but consider > > load_package specfn; > zeta(2); > 2 > pi > ----- > 6 > > > > Arthur > ```

 [Reduce-algebra-developers] Sum(1/x^2, x, 1, infinity); From: Michael Borcherds - 2012-07-30 13:18:04 ```Hi, Is there any way to get Reduce to calculate this? Sum(1/x^2, x, 1, infinity); thanks! Mike ```
 Re: [Reduce-algebra-developers] Sum(1/x^2, x, 1, infinity); From: Arthur Norman - 2012-07-30 14:40:21 ```On Mon, 30 Jul 2012, Michael Borcherds wrote: > Hi, > > Is there any way to get Reduce to calculate this? > Sum(1/x^2, x, 1, infinity); > > thanks! > > Mike > You may not like this answer, but consider load_package specfn; zeta(2); 2 pi ----- 6 Arthur ```
 Re: [Reduce-algebra-developers] Sum(1/x^2, x, 1, infinity); From: Michael Borcherds - 2012-07-30 15:05:00 ```Thanks, using specfn is an improvement as sum(1/x^2,x,1,infinity); then works! However these still don't :) sum(1/(x+1)^2,x,1,infinity); sum(1/x^2,x,2,infinity); thanks, Mike On 30 July 2012 15:40, Arthur Norman wrote: > On Mon, 30 Jul 2012, Michael Borcherds wrote: > >> Hi, >> >> Is there any way to get Reduce to calculate this? >> Sum(1/x^2, x, 1, infinity); >> >> thanks! >> >> Mike >> > > You may not like this answer, but consider > > load_package specfn; > zeta(2); > 2 > pi > ----- > 6 > > > > Arthur > ```