|
From: Sean L. <sea...@ic...> - 2018-04-18 16:43:03
|
Actually, that seems to have answered my question. I added all of these as config: AllowUnknownMsgFields ='Y' ValidateUserDefinedFields ='N' ValidateFieldsOutOfOrder='N' ValidateUnorderedGroupFields ='N' ValidateIncomingMessage ='N' And now I get the entire message. Thank you! On 4/17/18 11:32 AM, Colin DuPlantis wrote: > QuickFIX/J Documentation: http://www.quickfixj.org/documentation/ > QuickFIX/J Support: http://www.quickfixj.org/support/ > > > FieldsOutOfOrder ? > > Can you give us a sample message (redacted as necessary)? > > > On 04/17/2018 10:15 AM, Sean LeBlanc wrote: >> QuickFIX/J Documentation: http://www.quickfixj.org/documentation/ >> QuickFIX/J Support: http://www.quickfixj.org/support/ >> >> >> Hello, >> >> >> With Quickfix 1.6.3, as the initiator, I'm trying accept sent >> messages that violate the given data dictionary. I've tried a few >> things: >> >> 1. Setting UseDataDictionary to 'N'. This seems to work to get a >> corresponding message, but the application doesn't seem to get the >> entire message. The app gets a message, but it looks like it has >> fewer fields than the message logged in QuickFix/J's message log. >> >> 2. Setting AllowUnknownMsgFields to 'Y' and ValidateUserDefinedFields >> to 'N'. This seems to have no effect? QuickFix/J still seems to >> reject the message beforehand. >> >> >> ------------------------------------------------------------------------------ >> >> Check out the vibrant tech community on one of the world's most >> engaging tech sites, Slashdot.org! http://sdm.link/slashdot >> _______________________________________________ >> Quickfixj-users mailing list >> Qui...@li... >> https://lists.sourceforge.net/lists/listinfo/quickfixj-users > |