[Quickfix-developers] (no subject)

[abhijit <ab...@in...>]

I want to create a GUI based project. but when i'm call following part =
from my GUI Form, it's not work & "application.Run(new FIX_Acceptor.FIX =
())" code is automatic deleted.
SessionSettings settings =3D new SessionSettings( "hello" );

Application application =3D new Application();

MySQLStoreFactory factory =3D new MySQLStoreFactory( settings );

MySQLLogFactory logFactory =3D new MySQLLogFactory( settings );

MessageFactory messageFactory =3D new DefaultMessageFactory();

SocketAcceptor acceptor=3D new SocketAcceptor( application, factory, =
settings, logFactory, messageFactory );



Please give me some advice how i create a Gui based project with =
quickfix functionality.



Thanks

Avijit